can you help me how to solve ithi EYT1,
Please what you think the answer is to the question.
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A^2 +B^2=C^2Good grief. This problem is so easy it's trivial; any high school sophomore should be able to solve it.
The two currents are 90° apart; that is, they are at right angles to one another. What do the two vectors form if you connect their ends together? Have you ever heard of a right triangle? Have you ever heard of the Pythagorean Theorem?
If the above doesn't give you enough hints-- along with the hints in the original question-- to easily solve the problem yourself, you're probably hopelessly lost.
You're getting there; now, what are A and B?A^2* B^2=C^2
A - B side of right triangleYou're getting there; now, what are A and B?
3 amps and 4 ampers.So in the context of your problem, what are A and B?
c= 5 answerCorrect. So what is C?
is this the solution? is it over?Correct.
Specifically, 5 amps is the amplitude (the absolute value, or magnitude) of the resulting current when currents A and B are added. The Pythagorean Theorem works because the currents A and B are orthogonal-- that is, they're 90 degrees out of phase with one another and can be represented as the two sides of a right triangle.
Thanks. I have one more question Can you help with the solution?Yep. Sure looks like the solution, to me!
I could, but I won't. You're perfectly capable of figuring it out on your own.I have one more question Can you help with the solution?
which formula should i use?I could, but I won't. You're perfectly capable of figuring it out on your own.
Sorry, but you're going to have to figure that out yourself. I'm done here.which formula should i use?
This is the hard part for you.... understanding. Don't think about formulas yet, try to understand what it is you're trying to figure out. Or what it is you're starting with. The reason it's difficult for you is because the term 'phase' is foreign to your mind.Thanks. I have one more question Can you help with the solution?
One motor draws 20 Ampere lamp and 15 Ampere current. The current drawn by the lamp is in phase with the voltage; The current drawn by the motor is 60 degrees ahead of the voltage. What is the total current value drawn by the motor and lamps from the network by considering the voltage as zero phase? (cos60 = 0,5)
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