Hello. Here is my task: Oscillator circuit is shown. a) Calculate frequency of oscillations, b) Calculate minimum value R1 for which circuit still oscillates, c) Calculate amplitude of voltage VB, for which voltage VA start cuting off Vz=6.3V, R1=100K, R2=120K, R3=470, R4=2R6=10K, C1=C2=100nF, Vd=0.7V, R4=R5. I completed task a) and task b) I got f_oscillations=232.7Hz and R1_min=250k. I don't know how to solve task c) Any idea? Thanks in advance.
Well, find Vb/Va = gain for Fo and do you know the "cutting off" voltage for this simple diode limiter? VA start cutting off = "cutting_off voltage" * gain.
Do you manage to find the gain ?? I got this result : And Fo is around 147Hz Also as a side note I immediately recognized this circuit with OP2 alone, as is used in guitar effects http://www.muzique.com/news/wahantiwah-mod/
But the gain is depend on s. My formula is a valid only at Fo. And if you solve for Vb(s)/Va(s) you already have a voltage gain expression. All you need is to find gain at Fo frequency.
Jony30, I got same result as you in post #5 using analysis in post #4. I got w0=sqrt((R2+R3)/(R1*R2*R3*C1*C2))=924.3361 rad/s
Good for you. And the transfer function (if i do not make any error) in standard form is : T(s) = (a1*s)/(s^2 + ωo/Q + ωo^2) And the gain at Fo is Av =(a1*Q)/ωo = (C1 R1)/((C1 + C2) R2)