That's exactly what's happening.................
The reason that sounded weird to me is because it sounded like the Vout was making go through R1 from right to left.
That happens to be true here, only because R1 is the same as R2Shouldn't that read "...op-amp will output whatever voltage is needed to drop 6 volts across R2"?
I've visited a few sites in YouTube, electronics-tutorials.ws where they always use conventional current flow.That's exactly what's happening.
Vout is the controlled voltage which is forced to go to 12V by the op amp so that the voltage at the (-) op amp input is 6V to match the 6V at the (+) input.
(The diagram left-to-right arrows show electron flow from negative to positive. Conventional current flow would be right to left. Is that what you find confusing?)
Yes. I always use conventional current flow (which I find easier to understand), as do many references, but whoever did your reference tutorial was familiar with electron flow (I think it's used in all military electronics courses, for example) and thus wrote it with electron flow designations.I've visited a few sites in YouTube, electronics-tutorials.ws where they always use conventional current flow.
If we start at the very beginning, do you understand why an opamp is considered to have infinite gain ?In this part of Ch8
"If R1 and R2 are both equal and Vin is 6 volts, the op-amp will output whatever voltage is needed to drop 6 volts across R1"
Shouldn't that read "...op-amp will output whatever voltage is needed to drop 6 volts across R2"?
Do you understand that "electron flow" and "conventional flow" are models which people use to predict behavior? Do you understand that it doesn't matter which model you use, as long as you use it consistently? Both models work. You can use the one that is most convenient to you. What you can not do is insist that everybody does it your way.The reason that sounded weird to me is because it sounded like the Vout was making go through R1 from right to left.
EMFieldsIf we start at the very beginning, do you understand why an opamp is considered to have infinite gain ?
Infinite gain is required in an ideal opamp so that the output will be exactly 0V, if and only if, the differential input voltage is identically 0V. AFAIK a yoctovolt is the smallest unit of voltage with a named prefix. It is 1 x 10^-24 volts. In a ideal opamp, a differential input of 1 yoctovolt would send the output to the rail. In a typical opamp a differential input of 1 yoctovolt and a voltage gain of 120 dB, the output would be 1 attovolt (1 x 10^-18). Can you now see the difference?EMFields
Well no, I don't know why other than they are modelled to have infinite gain in the ideal model.
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