This looks homeworky. Is this homework?What is the difference between the two circuits?
I am not asking that.This looks homeworky. Is this homework?
Thinking more I think I can nudge this along whether it is or isn't homework. Try using KVL/KCL to see what the difference is. In other words, what are the voltages and currents through all the nodes/components?
Never mind the voltage and resistance. The current through each LED is same in both the cases. and the voltage (I think). Then how will the second will be a failure.Assuming you have the correct voltages and resistances - the one on the left has the potential to work whereas the one on the right has the potential for catastrophic failure.
Just so you know, the circuit on the right has the potential for catastrophic failure. First, your voltages and resistances are wrong. I won't focus on how or why. However, the reason why the one on the right is in danger of complete failure is because one of the diodes will hog the current. Meaning if you pump too much current through the circuit you will blow that hogging diode. Then the next diode will then hog the available current and blow. Finally the last one will blow. And it will happen VERY fast. You would likely not have sufficient time to shut down the circuit.I am just asking.
Just to know
Ok then. It's like this.No I am just asking.
Just to know
Say each led need 30mA to glow. So the source will provide 90mA total current. And the same 5V there across each led-resistor pair.hi shibin,
The right side circuit will work OK providing the LED forward voltages are matched ie: the same voltage.
They will share the 10k current equally, so be dimmer.
The left side circuit will work with any LED forward voltage, they do not need to matched for forward voltage.
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