Hello,

In ohm's law, there are four categories. The voltage, current, wattage and the resistance.

Voltage is measured in volts.
Current is measured in amperes.
Wattage is measured in watts.
And resistance is measured in ohms. Am I correct?

To get the ohms of one electrical device, I should divide voltage (volts by current (amps)? Am I correct?

Means, if I have 12 volts, 5 watts lamp. I will get about 0.4166666666666667 amperes.

12 divided by 0.4166666666666667 equals 28.799999999999997. Right?

Am I correct?

Thank you.

 

Hello,

Take a look at this pages from the eBook:
Chapter 2: OHM's LAW

• How voltage, current, and resistance relate
• An analogy for Ohm's Law
• Power in electric circuits
• Calculating electric power
• Resistors
• Nonlinear conduction
• Circuit wiring
• Polarity of voltage drops
• Computer simulation of electric circuits

Bertus

 

Looks right. Lightbulbs are complicated though, if you measured the resistance when not lit, it would be much lower. This is because metals increase in resistance as they get hotter, and the filament in a lightbulb is very hot.