Please solve this problem by using nodal voltage analysis method, i am so confused in it,
in this problem we have to find out the current I3.
Ok, i am attaching a file here plz solve this for me thanx.....
View attachment 5555555555.doc

 

Is this a homework problem?

hgmjr

 

No it is not,ACTUALLY I WAS TRYING TO SOLVE THIS BUT IT IS very very difficult.......
I shall be thank full to you if you solve this for me.....

 

If you don't have to use nodal analysis you can use some simplifying reductions to obtain the current in R3 (was that I3?). I haven't double checked my attached method - but the process would be a reasonable one.

 

The image which u have attached, is not opening.........?

 

It opens just fine for me.

hgmjr

 

I have same (correct!) answer as T N K.

Sadaf: Could I recommend that you try to get a LOT of practice solving networks. This process is fundamental to many branches of Electrical/Electronics Engineering.

 

I'm a huge advocate of Thevenin style methods (source transformations, equivalent resistances, etc.) like what t_n_k did over loop and nodal analysis.
Algebra is just lame I think, I avoid it wherever I can.
I do agree practice with it is important though, if only because sometimes you are stuck with nodal analysis.

 

Ghar - Use every trick (sorry, technique) in the book to get the correct answer to a problem with the least effort. Then verify the answer.
Algebra can sometimes be useful if a formula type solution is needed. Again, there are ways of verifying formula solutions.

 

Ok corleeee,but can you tell me if we take the directions of all currents at a node in such a way that they are leaving the node.......
Then in that condition will my answer is true if i take the direction of currents in such a way........?

 

Still not opening.............

 

Have attached the two solutions as they were posted - but in pdf format. You need to download them and open with a pdf viewer such as Adobe Acrobat. Hope this helps.

 

Here is the nodal solution if you are still interested.