x+y=13,200
1.05*X + 1.2*Y=15,090
for solving
(x+y=13,200) *1.05
1.05*x+y*1.05=13,860
1.05*X + 1.2*Y=15,090
- - -
____________________
0+0.15y=1230
y=8200
so, x+8200=13200
x=5000

 

Correct!

Do you want to do another exercise today?

 

yes, i want to increase study formula

 

Ok please give me a few minutes

 

Here it is:

The equivalent resistance, Req, of two resistors R1 and R2, placed in parallel is given by

\(
R_{eq} \: = \: \frac{R_1 \cdot R_2}{R_1 \: + \: R_2}
\)

Show that, if R1 ≤ R2, then

Req ≤ R1

and that

(R1)/2 ≤ Req ≤ (R2)/2

NOTE: I added a lower limit to the last one.

This is a very useful result as it allows you to place bounds on the equivalent resistance of parallel resistors (or inductors, or series capacitors) by inspection. And we've seen how useful bounds can be.

There's an even tighter upper bound: (R1)/2 ≤ Req ≤ (R1+R2)/4

 

There's an even tighter upper bound: (R1)/2 ≤ Req ≤ (R1+R2)/4

Sorry i don't know

 

Here ya go!

The perimeter of a triangle is 67 meters. The longest side is 8 meters longer than the shortest side, and the other side is 5 meters longer than the shortest side. find the length of each side.

Hint -- At ;first blush' this exercise may seem to require certain skills that it does not!

 

There's an even tighter upper bound: (R1)/2 ≤ Req ≤ (R1+R2)/4

I hesitate to administer Wbahn's exercise sans his presence -- I tend to be too liberal with 'hints' and to lenient as regards tracking of units

 

@RRITESH KAKKAR

Now that you know all about the mod's profiles -- how about attending your studies?

 

Hint -- At ;first blush' this exercise may seem to require certain skills that it does not!

??

 

Now that you know all about the mod's profiles -- how about attending your studies?

mean?

 

mean?

Merely that you were lollygagging about the site instead of attending to your studies

 

Please see post #667

 

The perimeter of a triangle is 67 meters. The longest side is 8 meters longer than the shortest side, and the other side is 5 meters longer than the shortest side. find the length of each side.

67=a+b+c
67=x+(x+8)+(x+5)
67=3x+13
67-13=3x
54=3x
a=x=18 the shorter
b=x+8=26
c=x+5=23

 

lollygagging
Idly wasting time, hanging around with no purpose.

 

??

No trigonometry required!

 

67=a+b+c
67=x+(x+8)+(x+5)
67=3x+13
67-13=3x
54=3x
a=x=18 the shorter
b=x+8=26
c=x+5=23

Very Good! You seem to have mastered these -- what would you like to move on to?

 

yes

 

yes

Give this a try: x^2+x+1=0 Solve for x

Hint 'parochialism' is the sole obstacle to solution of this exercise

 

Give this a try: X^2+x+1=0 Solve for x

For ax^2+bx+c=0
X^2+x+1
x=(-b±√(b^2-4ac))/2a
a=1 b=1 c=1
x=(-1±√(1^2-4*1))/2*1
x=(-1±√(1-4)/2
x=(-1±√(-3)/2
x=-1/2±√(-3)/2
x=-0.5±√(-3)/2