HP at rate you're going you'll be showing him the jacobian by next week! I say rigor is good but can be too much of good thing when it scares student away! I know you will say it worked for me but don't forget I'm not normal! !

 

at rate you're going you'll be showing him the jacobian by next week!

I think you'll never let me hear the end of that -- Seriously, do you really begrudge that past 'rigor' in light of it's instrumentality to you present 'fortunes' -- Think about it???

I know you will say it worked for me but don't forget I'm not normal!

--Emphasis added --

No fear of that!

All the best
HP

 

Why are you two talking in Greek ?

 

Why are you two talking in Greek ?

(Assuming you are referring to Aleph and I) Vector Calculus passes for Greek? -- I'll take your word for it - not being especially au fait with etymology...
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YO @RRITESH KAKKAR -- Truancy is bad scholarship!

 

not being especially au fait with etymology...

Come again.

 

Methinks you're having me on

 

I give up.

 

Me, I just munch popcorn and enjoy the shows.

 

I reckon no one here can win over HP in words

 

This quick repartee is having an effect on me, I'm going to take a post-prandial nap.

 

I give up.

I'm only sticking around to see how long this ridiculous thread gets before it dies. My guess: 500 posts, MINIMUM.

 

This quick repartee is having an effect on me, I'm going to take a post-prandial nap.

And I forgot about this one.

 

I'm only sticking around to see how long this ridiculous thread gets before it dies. My guess: 500 posts, MINIMUM.

Sadly, there would seem to be something to what you say Seems my 'pupil' is 'playing hooky' -- and after all my efforts on his behalf! - Whatta world!

@RRITESH KAKKAR
My offer yet stands -- 10 'like points' should you choose to solve the exercise presented by post #359
I should think academic achievement would be its own reward - still... whatever works...

Best regards
HP (The Ever Optimistic)

 

I should think academic achievement should be its own award - still... whatever works...

Ha Ha Ha Ha!!!! ROTFLMAO!!!

You've stated before that you are not, and have never been, a teacher. Now you have provided clear proof of that assertion!

 

Ha Ha Ha Ha!!!! ROTFLMAO!!!

You've stated before that you are not, and have never been, a teacher. Now you have provided clear proof of that assertion!

Touché -- As per my user name I am an inveterate student --- Also as per my username I have the utmost respect for bona fide instructors!!!

Sincerely
HP

 

Why are you two talking in Greek ?

Is not Greek I just reminding HP about math lesson she taught me once

 

Seems my 'pupil' is 'playing hooky'

HP Do you recall someone saying;

I say rigor is good but can be too much of good thing when it scares student away

 

---Edit @ 18:47 (UTC - 6:00) 10 Dec 2015 --- All typos 'eradicated'!---

As I understand post #357 you want a more 'interesting' exercise? -- Inasmuch you did well yesterday - I offer this fun exercise -- As incentive I will grant you 10 "likes" if you solve it!

What is the resistance apparent 'across' Nodes P and Q for the network pictured below?

Note: Please do not resort to analysis! -- Perhaps counterintuitively, this exercise is readily solved via purely algebraic techniques! I promise!!!

Hint 1: Note that the resistance of the semi-infinite 'section' is not altered via removal of preceding 'stages'...
Hint 2: Hint #1 is very important! -- Please consider it!
Hint 3: This is actually a very simple problem! -- Don't be distracted by 'infinity'...

You probably already know this -- however for completeness sake:
Resistors in series: Reffective = The sum of resistances (i.e. Reffective = R1+R2+R3...)
Resistors in parallel Reffective = The reciprocal of the sum of the reciprocals of the resistances (i.e. Reffective = (1/R1+1/R2+1/R3...)^-1

Again, do not use analysis (i.e. Calculus, etc)!!! -- Doing so will disqualify your answer!

OBTW Don't bother searching the web for the 'answer' - most sites offer incorrect solutions!

View attachment 96299

Hello,
Yesterday, i was at home.
as R is 1 ohm.
so, P & Q as you said Hint 1: Note that the resistance of the semi-infinite 'section' is not altered via removal of preceding 'stages'
it should 3 ohm
1+1+1=3

 

Hello,
Yesterday, i was at home.
as R is 1 ohm.
so, P & Q as you said Hint 1: Note that the resistance of the semi-infinite 'section' is not altered via removal of preceding 'stages'
it should 3 ohm
1+1+1=3

Let's ask if that answer makes sense.

If we remove all except the first three resistors, then the total resistance would be 3 Ω. But, in order for the solution to be 3 Ω when all of the resistors are in place, that means that adding back in all of those resistors, which are in parallel with the middle resistor of the three, has absolutely no effect on the resistance. Does that make sense? In fact, if the total resistance is 3 Ω, that means that the resistance of the section we removed was 3 Ω, which means that when we put it back in place we now have a total resistance of 1 Ω + (1 Ω || 3 Ω) + 1 Ω, which would be what?

 

then,
1+1.3+1=3.3