Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:

 

Here's your hint:

Hint: The difference in the trains' velocities might be regarded as 'rate' in this exercise

 

how to solve i mean i am not getting.

 

It's A Distance, Rate, Time problem

You know the rate is 10 km/Hr
You know the Time is 36 seconds
You know the distance is twice the length of each train...

 

It's A Distance, Rate, Time problem

How did you get that?
its on your tips?

 

You know the distance is twice the length of each train...

How?

 

You know the rate is 10 km/Hr
You know the Time is 36 seconds
You know the distance is twice the length of each train...

Distance=speed x time

 

How?

As per the stipulation:

Two trains of equal length...

 

ok, then how to move forward.

 

Distance=speed x time

You may regard 'speed', 'velocity' and 'rate' as synonymous for these purposes only

 

Please think about it! -- I've all but given you the answer in post #184

 

synonymous having the same meaning as another word or phrase in the same language.

Ok

 

It's A Distance, Rate, Time problem

You know the rate is 10 km/Hr
You know the Time is 36 seconds
You know the distance is twice the length of each train...

formula

 

synonymous having the same meaning as another word or phrase in the same language.

Ok

Yes, however only in this context for 'speed' and 'velocity'!!! --- 'Rate' and 'speed', however, are generally synonymous...

 

formula

You already know the formula -- you have stated it several times

Hint: You know the rate, you know the time, You want to solve for distance

 

HP, I truly admire your patience.

 

HP, I truly admire your patience.

That is indication of good personalities.

 

That is indication of good personalities.

Lemme tell ya! It's a necessity for anyone stepping into the role of an educator...

 

You know the rate is 10 km/Hr
You know the Time is 36 seconds
You know the distance is twice the length of each train...

ok, speed in mtr/sec will be 10 x 5/18= 2.77mtrs/sec
D = 2.77x36=100metrs
which is double so length i s50metrs

 

You know the rate is 10 km/Hr
You know the Time is 36 seconds
You know the distance is twice the length of each train...

ok, speed in mtr/sec will be 10 x 5/18= 2.77mtrs/sec
D = 2.77x36=100metrs
which is double so length i s50metrs

Congratulations! -- You've just earned another 'Miller' -- Well done!!!