ok, speed in mtr/sec will be 10 x 5/18= 2.77mtrs/sec
D = 2.77x36=100metrs
which is double so length is 50
meters

in morning i was doing the same but i was not getting answer.

 

@RRITESH KAKKAR

Please note that key to expertise with algebra (and, indeed, mathematics/science in general) is skill at statement, and hence, apprehension, of the 'problem'

 

Lemme tell ya! It's a necessity for anyone stepping into the role of an educator...

mean?

I remember Kubeek Sir.
He has teaches LCD 16X2 without micro and BJT.

 

Please note that expertise with algebra (and, indeed, mathematics/science in general) is statement, and hence, apprehension, of the 'problem'

meaning?

 

in morning i was doing the same but i was not getting answer.

You may benefit from a review of your errant work with an eye to avoidance of future 'pitfalls'...

 

MEAN IN SIMPLE ENGLISH

 

meaning?

Merely that recognition of 'problem type' is key to proficiency -- For instance, had you identified this as a "Distance, Rate, Time" problem at the outset - you would known exactly what was required...

 

ok, what is the application of these investigation or formula in life.

 

ok, what is the application of these investigation or formula in life.

Please rephrase that

 

what is the application of these investigation or formula in life.

What we will gain from these?

 

 

mean?

That, as regards instructors -- patience is not merely a virtue but an imperative!

 

what is the application of these investigation or formula in life.

What we will gain from these?

The ability to comprehend and predict --- IOW to 'embrace' humanity's 'manifest destiny', as it were

 

@RRITESH KAKKAR

Time for me to 'sign off' --- I'll look in on the thread same time tomorrow

 

Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:

 

Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:

HINT: Relative rate (for these purposes) represents an 'absolute value' (i.e. magnitude) hence opposing rates 'add' -- à la positive values...

See you tomorrow!

 

done

 

A train travelling at a speed of 75 mph enters a tunnel 3

miles long. The train is

mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?

 

A train travelling at a speed of 75 mph enters a tunnel 3

miles long. The train is

mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?

Do it yourself. Stop asking for answers here. You've been given more than enough examples to figure it out on your own.

 

i want calculates milephr to mtr/sec