Not even that "bit of algebra" available Mathew?Yippy, a quiz.
OK, was you hoping that I'd show you? Cause I found that equation; It's all over the place.
I was kind'a hoping to get an equation to solve "t"
\(\frac{v}{5} = 1-e^{\frac{-t}{RC}}Let's see a +5V source
R=1.62 MΩ
C=10nF
The response of an RC circuit is
\(v=5(1-e^{\frac{-t}{RC}})
\)
You should be able to answer your own question with a bit of algebra
Guess not.\(\frac{v}{5} = 1-e^{\frac{-t}{RC}}
\frac{v}{5}-1=-e^{\frac{-t}{RC}}
1-\frac{v}{5}=e^{\frac{-t}{RC}}
\)
Take the natural logarithm of both sides
\(ln(1-\frac{v}{5})=ln(e^{\frac{-t}{RC}})
\)
Can you take it from there?
Too true, my friend, all too true.Doesn't matter. He only has enough fish for a day -- not enough to feed himself long enough to get a degree.
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by Jake Hertz