Hi, there are 12 solar cells. So It's total output voltage is 0.6Vx12= 7.2V
I want to bypass solar cell 1 using MOSFET when in shadow.
Gate voltage req for this MOSFET is 2-4 V. I did this above circuit. This works only if 4.9k is connected to bench supply but doesn't work if connected as in above circuit.
Can you please help me to know why it works when 4.9k resistor is connected when given supply separately and doesn't work if 4.9k resistor and drain is connected to the positive terminal of the cell?
Also if there is any modifications required in the circuit please do let me know. Thank you.

 

Consider that if the LDR is not illuminated it's resistance will be very high. and turning on the MOSFET requires a high gate to source voltage which does not appear to be provided by the circuit shown.
To provide a bypass for a non-illuminated solar cell, why not simply shunt it with a shotky diode that would be reversed biased when the cell ids illuminated??