Consider a 386 system and it has 40 address lines, calculate the total memory it can address. Design a logic circuit to address three 1024 MB RAMs and two 512 MB RAMs .

My attempt is (just giving it a try)

1) Consider a 386 system and it has 40 address lines, calculate the total memory it can address.

=> 2^40 x 4 bytes

2) three 1024 MB RAMs and two 512 MB RAMs

=> one 1024 MB can be addressed by 30 address lines, so three 1024 can be addressed with 32 address lines and for a 512 MB ........stuck from here

 

Answer deleted, due to being seen as a complete answer, rather than just a suggestion.

 

1) Consider a 386 system and it has 40 address lines, calculate the total memory it can address.

=> 2^40 x 4 bytes

2^40 x 1 byte=......bytes

"32-bit addressing, allowing it to address up to 4 gigabytes" from:
https://en.wikipedia.org/wiki/RAM_limit