Making a 2 terminal Current Regulator

Ian0

Joined Aug 7, 2020
13,132
I'm probably showing my age calling it a "bandgap reference" - they just seem to be called voltage references these days.
Originally they were only available in 1.2V, (the bandgap voltage of silicon) but now there are versions for any voltage you might fancy.
The basic premise is to take two semiconductor junctions and make sure that the current through one is ten times the current through the other. Because of the exponential relationship between I and V it follows that if I2/I1 = 10 then V1-V2 = 60mV.
There's a good explanation in Horowitz & Hill and also on Wikipedia https://en.wikipedia.org/wiki/Bandgap_voltage_reference
 

Thread Starter

Wendy

Joined Mar 24, 2008
23,798
Sounds like something I've been looking for years. Thank you.

That would have worked on my original concept.
 
Look here: https://sound-au.com/ism.htm They don't explain the FET version very well. They brushed it off.
turn that into a low leakage fast 38 kHz LED driver at 50-100 mA that I can understand, I'm interested.

Analog devices has a 2T current source. The LM334 is very temperature dependent.

I made a +-50 mA variable current source.
 
Last edited by a moderator:

AnalogKid

Joined Aug 1, 2013
12,141
Last edited:

Thread Starter

Wendy

Joined Mar 24, 2008
23,798
As I said, I'm not after a circuit per se but a really low CC circuit. Parts are on order, so I will get back to this thread.
 

atferrari

Joined Jan 6, 2004
5,012
To drive a sensor requiring a very small current <500 uA, I used the LM 334 with one of the reccommened circuits in the datasheet to reduce the effects of temp / voltage variations.

That was maybe around 20 years ago. Should look for details if required. Circuit was extremely simple.
 

Thread Starter

Wendy

Joined Mar 24, 2008
23,798
So, the parts arrived yesterday. I'm testing this design 1st, because the parts are something a home experimenter might have. I'll post the results when I have them. I give this circuit the smallest chance of working, but their will be more contenders.

0 temp.jpg

The Data

Volts Ic Q1bv
2.0 0 50.6µa 0.442V
3.0 90.0µa 0.490V
4.0 140.7µa 0.524V
6.0 250.0µa 0.571V
8.0 359.0µa 0.604V
9.0 1033µa 0.617V

I would call this one a bust, NEXT she yelled.
Q1bv is Q1 Base Voltage.
 

Thread Starter

Wendy

Joined Mar 24, 2008
23,798
OK. Referring to post 11 I will try this circuit...

0 temp.jpg

Guess I'll be doing the math check tomorrow (this is not the final circuit.)
 
Last edited:

Thread Starter

Wendy

Joined Mar 24, 2008
23,798
Disappointing
2V 12µa
4V 19µa
6V 25µa
8V 51µa
10V 63µa

It didn't help when I blew a 600ma fuse in my DVM. So I dusted off a spare, ordered more fuses from Amazon. Tomorrow I will try a 16KΩ resistor and will post the results again.
 

crutschow

Joined Mar 14, 2008
38,520
Here's a sim using the 2 BJT constant-current circuit in a bridge configuration.
The circuit needs a supply voltage of at least 7V for reasonable linearity.

1617339922376.png
 

Thread Starter

Wendy

Joined Mar 24, 2008
23,798
Helps if you install the chip correctly, so after reorienting it correctly and updating my personal Paint CAD files it now regulates to 0.8V! I did have to adjust the formula empirically.

It seems to be (for this individual chip):

\(Icc=\frac{0.06513}{R1}\) or \(R1=\frac{.06513}{Icc}\)

0 temp.jpg

So, for 620Ω I got a flat 106 µA across the board. Regulation stopped right under 0.8V, so a conventional diode bridge should work down to almost the full range of the 555 CMOS or not. For complete results I will test the bandgap reference next.

We have a winner in any case! I love the simplicity!

I attached a worksheet if anyone is interested.
 

Attachments

Last edited:

Thread Starter

Wendy

Joined Mar 24, 2008
23,798
I've always liked this circuit, each half puts a constant current through the opposite reference.
For really low current you can't beat a bandgap reference, but I think LEDs might workView attachment 233391
For the 555 oscillator you need a bidirectional source, but if you use two similar circuits in anti-parallel you risk their not being quite similar, but you can put a single circuit inside a schottky-diode bridge.
So I'm just about ready to try this. to limit current in only one direction what Resistor values do you recommend? Which one programs the current? So if I use x100 for the other would that work?
 

Ian0

Joined Aug 7, 2020
13,132
So I'm just about ready to try this. to limit current in only one direction what Resistor values do you recommend? Which one programs the current? So if I use x100 for the other would that work?
Both R values are the same. The current in each side is half the total, which is (Vref-Vbe)/R.
So for 1.2V reference and Vbe of about 0.6V, total current = 1.2/R
 

Thread Starter

Wendy

Joined Mar 24, 2008
23,798
OK, Figuring a minimum current to bias the LM4041 is 60µa And minimum bias voltage is 2V. R = 13KΩ, call it 10KΩ. So I will try this schematic...

<drawing>
 
Top