Hi, I’m having trouble drawing the following logic circuit, I was wondering if anyone could actually draw this circuit?

Draw the following logic circuit.
---------- -
(AB) + (C+D) + (AD)(B+C)
(5 marks)


As u know the lines above means that specific section of the sum has been knotted.

Any help would be excellent and much appreciated

Thanks
Scott

 

Having problem is OK. But could you please elaborate why and how you struggle?

 

You have more -'s (NOT)s than letters.

Quote this post and add/remove the overlines as needed:

\((\overline {A \cdot B}) + (\overline C \cdot \overline D) + (\overline A \cdot \overline D) \cdot (\overline B + \overline C)\)

See This Link for details.

 

(AB) + (C+D) + (AD)(B+C)

thanks

 

the under lined parts are the knotted, so theroically the line should be on top onf these letters.

thanks

 

\overline{A}

 

you need to put \( tags around the parts to be rendered in TeX

\(\overline A\)

is \overline A inside {tex} and {/tex} tags (replace { with [ and } with ])

If you hit the "Quote" button on the post where I added overlines to everything, you can see how it is done, and edit to match your formula.

You can hit "Preview reply" several times to get it to look correct before finally hitting "Submit".\)

 

sorry, but i need the circiut by tommorrow night to hand in to college or dont think i will pass, if at all you could draw it up for me i would be really gratful.
the under lined parts are menat to be overlined, sorry but i dont under stand how to over line it, how you can see around this, and hopefully be able to do the circuit.
you can use online logic gate creator software for free to create it.

thanks

 

It is time for you to do some participating:

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It would be nice of us to do your assignment, but then it wouldn't be your assignment.

 

(AB) + (C+D) + (AD)(B+C)

thanks

Let's just go with this. The goal here is for you to understand how to solve the problem of turning this Boolean expression into a functional circuit, not necessarily to learn Tex (the expression editor on this bulletin board).

Have you attempted to simplify this Boolean expression yet?

If not, why not? That is your first step.

If you forgot how, look in your textbook under Boolean Algebra.

We cannot do it for you, but we can nudge you in the right direction.

 

If you haven't yet, you might want to pay special attention to anything about De Morgan's laws, it may help here (or maybe not!).