Is my solution or the solutions manual incorrect?

Thread Starter

Aria Nemati

Joined Jul 19, 2019
26
I have the circuit:
enter image description here
where
enter image description here

According to the solutions manual. The answer is:
enter image description here

This is what I calculated:

enter image description here

As you can see. The only difference is that I did

$$\frac{1}{10}−\frac {j}{10}+\frac{1}{8+j6}$$ instead of $$\frac{1}{10}+\frac {j}{10}+\frac{1}{8+j6}$$​
 

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Thread Starter

Aria Nemati

Joined Jul 19, 2019
26
When you take the reciprocal it disappears.
\[ \frac{1}{j}\;=\; -j \]
Right?
Ok. I'm getting confused now. I just did a problem that is almost the same and got the correct answer. So what is the difference that I have failed to see?

1574656831453.png


Now I did the same problem the way I am supposed to and I get a wrong answer:

1574659574235.png

The angle is wrong. It should be positive not negative. So what am I doing wrong here?
 
Last edited:

The Electrician

Joined Oct 9, 2007
2,767
How do you know what the correct solutions for post #5 and #6 are? Are those also worked out in a solutions manual? If so, post the solutions given in the solutions manual.
 
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