I have the circuit:Attachments
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When you take the reciprocal it disappears.But Zc is negative. Where does the negative sign go?
Ok. I'm getting confused now. I just did a problem that is almost the same and got the correct answer. So what is the difference that I have failed to see?When you take the reciprocal it disappears.
\[ \frac{1}{j}\;=\; -j \]
Right?