Is it possible to amplify the signal of 5Vpp to 100Vpp with a common base amplifier?

 

Hi Mars,
Did you have a simple diagram you could post.
An amp is possible but would require dual supplies

E

 

안녕 마스,
게시할 수 있는 간단한 도표가 있으셨나요?
앰프는 가능하지만 이중 공급 장치가 필요함

E

I don't have a diagram, but I have a transistor data sheet.
https://assets.nexperia.com/documents/data-sheet/BF820W.pdf

Could you explain the dual supplies in more detail?

 

Hi Mars,
Did you have a simple diagram you could post.
An amp is possible but would require dual supplies

E

I've been copying a pcb board. I've been drawing the confirmed parts in a diagram so far, but I think I still missed a lot of parts (it's impossible to track them anymore).

Voltage Multiplier output is about 1kV. Therefore, it is estimated that the output voltage of BJT is 80 to 90 Vpp. There is no bias positive voltage in the diagram. (I think I missed it.) BJT is most similar to Common Base. Therefore, I am wondering if it is possible to make about 100Vpp with Common Base output.


Here is a diagram.

[/QUOTE]

 

Well, at least the transistor is properly specified. The datasheet for the BF820 says 300V max, so well within its rating.

 

Reminder Common base | Active_loads - Wikipedia

 

Well, at least the transistor is properly specified. The datasheet for the BF820 says 300V max, so well within its rating.

Thank you. Do I need a bias positive voltage of similar magnitude to amplify the signal at 100Vpp?

Reminder Common base | Active_loads - Wikipedia

Thank you, but i don't understand ,,,
Does it require a large Rc resistance to increase the voltage gain and a large Vcc accordingly?

 

Is it possible to amplify the signal of 5Vpp to 100Vpp with a common base amplifier?

Vin 5vp-p, Vout 98Vp-p, F=1khz. Common Base Amp.

 

Maybe I missed something, but what kind of signal would you amplify?

 

I would suggest you review articles on "cockroft walton voltage multiplier". There is at least one mistake in your schematic there. Also, the C-W multiplier likes to be driven by a fairly symmetrical driver. For your design the "output" transformer (to the right of BD5) is critical to operation. FWIW I don't see the needed power feed to the BC87-BC89 side of the output transformer.

 

Does it require a large Rc

it means a relatively high output impedance but also high dissipation on the transistor (at your case) - making it alone not very practical option in most cases
as with more figures for the ; #8

 

I would not use a multiplier at all but that is just because I use transformers.
I would not use a linear amplifier to drive a transformer or multiplier. I use MOSFETs in a on or off condition and never in a linear mode.
What output voltage and current/power do you want?
What is the input voltage?

 

Is it possible to amplify the signal of 5Vpp to 100Vpp with a common base amplifier?
the board you are copying is a high voltage Mutiplier ladder supply likely for a color CRT. The output voltage will be more like 20Kv. The diodes in the ladder are special high voltage ones to do the multiplication as are the capacitors which are from Japan. U8 is a biphase oscillator chip likely a from Exar and only has a partial number due to the small size. The circuit looks fairly complete but I would question some of the component values you have may not be correct. You do not need an amplifier here.