Please see the circuit diagram as attached.
Given values are: β = 100, VBE= 0.7V, VCE= 0.3V and VA= infinite
Notice: base and collector are grounded!
We have to find Ve and Ic
I have come up with the following solution
I applied Thievenin's theorem and found: Vth = 5/(1+1) = 2.5v and Rth = 1||1 = 0.5 KΩ
I consider the pnp transistor is operating in the active region and base is forward biased and collector is reverse biased.
So, Ie = (2.5-0.7)/0.5 = 3.4 mA and Ve = 0.7 volt
Therefore, Ic = αIe = β/(1+ β)*Ie = 0.99*3.4 = 3.36 mA.
Anybody wants to correct me if I'm doing anything wrong here?
Thanks
Given values are: β = 100, VBE= 0.7V, VCE= 0.3V and VA= infinite
Notice: base and collector are grounded!
We have to find Ve and Ic
I have come up with the following solution
I applied Thievenin's theorem and found: Vth = 5/(1+1) = 2.5v and Rth = 1||1 = 0.5 KΩ
I consider the pnp transistor is operating in the active region and base is forward biased and collector is reverse biased.
So, Ie = (2.5-0.7)/0.5 = 3.4 mA and Ve = 0.7 volt
Therefore, Ic = αIe = β/(1+ β)*Ie = 0.99*3.4 = 3.36 mA.
Anybody wants to correct me if I'm doing anything wrong here?
Thanks