Thank you. Want you and everyone to know none of this will be wasted. I will be studying everyone's equations. Also what circuit were you referencing in this post?I think he means that his 13.2V battery (two lead-acid 6V batteries in series) can supply 3A. But the max amplifier peak output current will not be 3A, it will be about (13.2V - 3V)/2= 5.1V peak/4 ohms speaker= 1.28A and the max output power will be (1.28A x 0.707) squared x 4 ohms= 3.6W RMS. The amplifier will heat with 1.4W. If he bridges two of these amplifiers then the peak output current will be 1.28 x 2= 2.56A and the output power will be about 12.6W. The amplifier will heat with 5W.
The average power from the amplifier will be about (3.6W + 1.4W)= 5W x 0.1= 0.5W if the amplifier is not bridged and is playing music so it is almost clipping. Then the average battery current will be about 120mA (a guess). A 7Ah battery charge will last 7/0.12= 58.3 hours.
Calculate how long the battery charge will last yourself when the amplifier is bridged.