The formula V = IR is wrong in my opinion. The equations should be written as I = V / R because I is the result of a voltage and resistance
They're equivalent; how you arrange the variables depends on what you're solving for.Neither is right or wrong.
There are a whole series of articles on that very subject that are right at the top of this forum.Hello, I am having trouble understanding what affects amerperage. Is it the wire diameter? When voltage goes up does the amperage go up? Does a metal object with a large diameter create low amperage?
An equation is usually expressed in a way that shows how something comes about. So for example, tax amount = your income * some factor would be right not income = tax amount / some factor.They're equivalent; how you arrange the variables depends on what you're solving for.
The two equations you mentioned in your post are equivalent so neither could be considered wrong. They were just manipulated with algebra to solve for a different variable.An equation is usually expressed in a way that shows how something comes about. So for example, tax amount = your income * some factor would be right not income = tax amount / some factor.
@dl324 What I am trying to say is that when people are taught they are taught V=IR which makes people think that current + resistance = voltage when the truth could not be further from that. Of course algebra can be used to rearrange it but when it comes to defining terms I should be the subject of the formula.
Why does it matter if it's a simple algebraic manipulation to put it into any form you want?Of course algebra can be used to rearrange it but when it comes to defining terms I should be the subject of the formula.
This basic stuff interests me greatly.
Dendads analogy confuses me a bit more.
Doesn't increasing the pressure (volts), cause a potential for an increase in current flow ?
In a simply 9 volt, 1 lamp circuit drawing 5 miliamps, wouldnt the current flow of 5 miliamps stay the same even if the voltage was doubled ?
George KG5TKY
You'll be further ahead in the game if you don't use the water analogy as a crutch.Doesn't increasing the pressure (volts), cause a potential for an increase in current flow ?
If the resistance of the lamp remains constant, Ohm's Law tells you the current will double if the voltage is doubled:In a simply 9 volt, 1 lamp circuit drawing 5 miliamps, wouldnt the current flow of 5 miliamps stay the same even if the voltage was doubled ?
Yes. That is what I thought I said.Dendads analogy confuses me a bit more.
Doesn't increasing the pressure (volts), cause a potential for an increase in current flow ?
If the pressure (voltage) goes up, more water flows.
I humbly a base myself before you and Mr. Ohm.Yes. That is what I thought I said.