I am stuck with this program. I don't understand the conditions in nested loops.
Another thing if number is 2, j<=(¡/j) because j=2. 2 divide by 2 is not greater or equal to j then condition is false then what would be output.pleae also elaborate your answer.!
I'm really stuck with it.

#include <stdio.h>
int main ()
{ /* local variable definition */     int i, j;
   for(i=2; i<100; i++)   
 {         for(j=2; j <= (i/j); j++)

Moderators note : split into lines and used code tags

 

Hello,

The posted programs is not complete.
There are two opening curly braces , but no closing.
Can you post the complete program.

Bertus

 

#include <stdio.h>

int main ()
{ /* local variable definition */
int i, j;

for(i=2; i<100; i++)
{
for(j=2; j <= (i/j); j++)
if(!(i%j))
break; // if factor found, not prime
if(j > (i/j))
printf("%d is prime\n", i);
}

 

I don't understand the condition in loops.Just clear my concept

 

I think you should run your program with the debugger enabled and watch output for each step to understand your code behavior.

 

I don't understand the condition in loops.Just clear my concept

It would be helpful if you framed your question more clearly.

Do you not understand what the conditional expressions do? Or do you mean that you don't know how nested loops work?

 

I don't understand the condition with in loops for prime number.How this condition work

 

I don't understand the condition with in loops for prime number.How this condition work

Do you not understand conditions within the loops, like i%j?

Or do you not understand conditions as a parameter in the for statement, like j<=(i /j)?

I think you mean the latter. For each repetition of the loop, the current values of i and j are used to calculate i/j. If the value of j is less than or equal to that result, the loop stops.

 

Do you understand what's happen in nested loop

This may be help you

#include<stdio.h>

int main(void)
{

  int i = 0;
  int j = 0;


  for ( i = 0; i < 5; i++)   // Outer loop
  {
     printf(" i = %d \n", i);
      for ( j = 0; j < 5; j++) // inner loop
     printf(" j = %d \n", j);
  }

    return 0;
}

Output of program

i = 0
j = 0
j = 1
j = 2
j = 3
j = 4
i = 1
j = 0
j = 1
j = 2
j = 3
j = 4
i = 2
j = 0
j = 1
j = 2
j = 3
j = 4
i = 3
j = 0
j = 1
j = 2
j = 3
j = 4
i = 4
j = 0
j = 1
j = 2
j = 3
j = 4

 

I don't understand the condition in loops.Just clear my concept

Even after you're told how to use code tags, you refuse:

#include <stdio.h>
int main () {
  int i, j;
  for (i = 2; i < 100; i++) {
    for (j = 2; j <= (i / j); j++)
      if (!(i % j))
        break;          // if factor found, not prime
      if (j > (i / j))
        printf ("%d is prime\n", i);
  }
}

Is this school work?

 

Where did this code come from? It looks like this is some kind of assignment where either you are given some code and asked to determine how it works, or you are given a problem and asked to develop some code to solve it. How we interact with you depends on which it is. But in either case you need to show your best efforts to do what the assignment calls for and we will try to help you identify and correct specific points on which you are going astray. We won't do your work for you as that will rob you of the learning opportunities that the assignment is intended to provide.

For starters, do you understand the problem that the program is trying to solve and the basic strategy that is being employed? Could you describe, to a sixth grader who knows nothing about computer programming, how to apply this strategy in such a way that they understand it and could do it with pencil and paper?