Hello everyone, I wish to transfer power at a distance of 10-15 feet using Infrared diode/LED. I need 3-4V at receiver side. I have used normal IR diode of AC remote control, modulated by 38 to 100 kHz as a transmitter and photo-diode as a receiver. I have already tried to transfer the power, but unable to do the same. Please suggest me about the required components and circuit for transferring the above mentioned power.
Can any one help me?

 

Define power. You must give a value for current required at your 3 or 4 volt level.
ie. 10 milliamps

 

Define power. You must give a value for current required at your 3 or 4 volt level.
ie. 10 milliamps

I need 3-4V at receiver side. to get this what have to do. viz, input voltage, current, components etc. Please suggest me the procedure from beginning.

 

I have already tried to transfer the power, but unable to do the same

You haven't answered Kermit re the current. Power = Volts times Amps.
Are you getting a measurable signal from the photo-diode?

 

You haven't answered Kermit re the current. Power = Volts times Amps.
Are you getting a measurable signal from the photo-diode?

I got 0.5V at photo-diode at a distance of 5 cm.
I wish to know from where to start to build this project

Define power. You must give a value for current required at your 3 or 4 volt level.
ie. 10 milliamps

current is 50milliamps

 

Define power. You must give a value for current required at your 3 or 4 volt level.
ie. 10 milliamps

0.7 milliamps

 

You haven't answered Kermit re the current. Power = Volts times Amps.
Are you getting a measurable signal from the photo-diode?

0.7 milliamps

 

50mA or 0.7mA ?

 

50mA or 0.7mA ?

0.7 mA.

 

50mA or 0.7mA ?

Please suggest about necessity current, voltage or any other components to develop the project

 

That means you need 0.0007 X 3 = 2.1 milliwatts

Your best bet is to use 20 or 30 LED's and a bunch of solar cells.

It's quite a large amount of power to move photonically with simple parts.

 

In a single word. No,
You cannot do it.

 

So. Worst case scenario:
0.7 mA
4 V
Distance of 15 feet (about 5 meters)

Power=0.7 mA x 4 V=0.0028 Watt=2.8 mW

You say you get .5 V at 5 cm. I don't see how you are going to get anything at 5 meters.

 

The overall efficiency of this would likely be no more than a couple percent.
You might try a high power IR LED such as one of these inside an appropriate (large flashlight type) reflector to beam the light at a small solar panel.

 

That means you need 0.0007 X 3 = 2.1 milliwatts

Your best bet is to use 20 or 30 LED's and a bunch of solar cells.

It's quite a large amount of power to move photonically with simple parts.

I have supplied power to IR LED from function generator.
Then what will be the input current to get the result. And how?

 

Why do you want to do this? You have not really explained your project with any detail.
To power something with IR is VERY inefficient. A bit more information will help. For instance, why cannot you just use a solar cell and sunlight?
To get help in something like this you do need to tell us what you are trying to do. What are you wanting to send power to, and what from.
Just putting an IR LED on a function generator will not give you any power to speak off. You are probably going to have to use an amplifier and an array of LEDS or a big power LED running watts to get a few mW at the other ind and use solar cells, not photodiodes.
Are you just trying to power something or communicate with it too?
"Need Input" to quote Number 5 from the movies

 

This problem is related to the design of an SMPS (Switched Mode Power Supply) in the following way:

The power output will always be less than the power input. Sometimes it will be a great deal less than the power input.​

I too was amused by the notion of extracting power from a function generator. That was a real knee-slapper.

 

The fact that he is driving the LED by a function generator, and using a photodiode as a detector makes me think he is stating the problem incorrectly. I think he is trying to transmit a signal, not power.

Bob

 

The fact that he is driving the LED by a function generator, and using a photodiode as a detector makes me think he is stating the problem incorrectly. I think he is trying to transmit a signal, not power.

Bob

Except for the title of the thread, you might have a point.

 

Well....
I dont think its a good plan per se but if you had too using available thgecnologies...

How about substituting IR for green at around 500nm so it will actually work with current solar cells, given that anything above 700nm or below 350nm is basically not worth having in this context.

Take a green laser and point it into a box lined with solar cells and containing a small convex target mirror as a decolumnator.
Granted hardly efficient but probably single figures.

And if it must be IR... Then go long, still with a laser diode but use a black body receiver, set at a low incidence angle to spread the beam, with high thermal conductivity and a TEG stack to extract the power.

I think saying you cant easily transmit power with photons is not entirly true, though I will conceed its hardly a good plan without a very speciffic application.
However laser cutting is nothing but photonic energy transfer to a precise location so I dont thin you can call it a bust either.

I would like to bet you could run a TEG based stove fan with a small array of IR laser diodes.

If you assume that the TEG is no m ore than 12% efficiant and then knock of 25% of that to a account for a poor receiver setup you still get circa 9% of what you sent which could easily be a watt with just one readily available diode.

Just musing...
Al