How to keep TMUX1108 and TMUX1104 disabled at power-up when using a shared MCU enable signal with inverter?

Thread Starter

hoyyoth

Joined Mar 21, 2020
528
Hi,

I am working on a design where I need to control two TI analog multiplexers — TMUX1108 (8:1) and TMUX1104 (4:1) — using a single enable signal from a microcontroller. When I am using 4:1MUX data the 8:1 MUX must be disabled. The setup is as follows:
  • The MCU provides one GPIO as the Enable source.
  • TMUX1108 receives this signal directly.
  • TMUX1104 receives the inverted signal through SN74LVC1G04DBVR (single inverter).
  • Both EN pins have 10 kΩ pull-down resistors to GND.
  • All devices operate at 3.3 V.
Issue: At power-up, before the MCU initializes, the inverter input is at GND (due to the pull-down), so its output goes HIGH. This enables TMUX1104 immediately after power is applied, which is not desired. I want both multiplexers to remain disabled after power-up until the MCU explicitly enables them.
1767106111208.png

May I know,

What is the best way to ensure both TMUX devices are disabled at power-up
 

Ian0

Joined Aug 7, 2020
13,097
Use a 74LVC1G240, which has three-state outputs. Connect the processor to the OE pin. The outputs will be disabled until the processor starts running its program, and the pull-down resistors will keep the multiplexers disabled.
Alternatively, use a 74HC139 and connect one MUX enable to each output (there are four outputs, you will only need two) then its enable pin will switch both off.
 
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