You must be on his "blocked" list.How would you even know the wire was at 500°F? You might be able to use the conductivity of the wire itself as a measure.
I'll ask it again - why not cook it in a temperature-controlled oven?
You must be on his "blocked" list.How would you even know the wire was at 500°F? You might be able to use the conductivity of the wire itself as a measure.
I'll ask it again - why not cook it in a temperature-controlled oven?
so you should just have asked... It was 3ft.as shown above copper wire has a specific resistance per foot (and that changes based on temperature too)..
Hence I was inquiring about how long your wire was to show why the dimmer overheated..
There is a big difference in trying it with 2 inches of wire vs 3ft of wire
The experiment is to heat treat with a DC current, not in an oven.You must be on his "blocked" list.
OK, but we're talking about a hair-thin piece of wire here. Doesn't that play a role on determining the current?Ok, going from the chart by Dickcappels in post#13, the resistance at 500F(260C) would be Approx 160 ohms, so a 1 amp current will need 160V minimum.
No way to tell how that dimmer works, but it is a good bet that is varies the voltage rather than the current -though there are few clues in the photograph, it does not appear to merely be a rheostat or pot.
I'm sure it can be done with AC, but that creates other issues, such as safety for instance. Thanks for the information, but I'm still not clear about how to put all the things people are saying here together. The experiment is to find out how extra stages and intensities of heat treating can change certain characteristics of the wire.heat treating can be done with ac also, we do it all the time here.
I just looked up the resistance of copper wire, #45 should have a resistance of around 10,000 ohms per 1,000 feet. your 3 foot piece would be about 30 ohms. the ampacity of #32 wire, .008 inch diameret is .53 amp in free air. the ampacity of #45 wire is less, probably .3 amp max. since most copper wire is annealed anyway, why would you want to soften it again?
Yes. The chart only gives the resistance, and only for that particular sensor in air. Doing a mind experiment, 1 amp at 160 volts cannot be the requirement. That's 160 watts, and a 500 °F temperature can easily be achieved by a 15-watt soldering iron, heating a much larger mass than a short length of #45 wire.OK, but we're talking about a hair-thin piece of wire here. Doesn't that play a role on determining the current?
no way I can't do that... I have limited resources here. What you said makes sense to me, but I'm still trying to understand how to actually do this. Dick Cappels suggestion seems the way to go so far. By the way, oxidation happens on the surface only, right? If so, it can be eliminated with a vinegar/salt bath. That's not an issue here.Yes. The chart only gives the resistance, and only for that particular sensor in air. Doing a mind experiment, 1 amp at 160 volts cannot be the requirement. That's 160 watts, and a 500 °F temperature can easily be achieved by a 15-watt soldering iron, heating a much larger mass than a short length of #45 wire.
Just like heating your house in winter, I think [thermal] insulation would be the key to heating the wire without much power. Are you allowed to wrap the wire into a small coil shape (non-shorting), and put the whole works in a vacuum? That would cut down on convective losses, and oxidation, too.
Its a PWM dimmer.. It "dims" by turning the output voltage on and off quickly.. Your multimeter will read 12V because its not fast enough to see the waveform.I measured the voltage and it stays fixed at 12V.
Its a PWM dimmer.. It "dims" by turning the output voltage on and off quickly.. Your multimeter will read 12V because its not fast enough to see the waveform.
If your wire was an LED it would change the "brightness" because that LED would be turning on/off quickly and persistence of human vision will see that as a difference in brightness.
https://learn.sparkfun.com/tutorials/pulse-width-modulation
back to resistance
Set your meter to measure resistance and see what your 3ft of wire measures..
From the chart I found for 45 awg wire its 3348 ohms per thousand feet.. So 3 ft would be around 10 ohms..
With a 12V source that would be 12/10 = 1.2 Amps (at room temperature)
You need more voltage..


Says who?The experiment is to heat treat with a DC current, not in an oven.
Thanks a lot, Dick.Just to add my 2 cents... It seems that this is the perfect time for an experiment!
I would use a constant current source and carefully creep up from a very low current. Definitely use a DC constant current source such as the ones recommended by Dodgydave or an LM317 connected similarly to the Instructables article. The reason to avoid your dimmer is that without know any particulars it is not clear whether the measured values are valid.
Unless you can get specific advice from somebody who's done this before you won't really know what to do until you start doing it (@alfacliff seems to be your go-to person for this).