How to create "DC offset voltage" in crystal oscillator ?

Bordodynov

Joined May 20, 2015
2,468
Usually (when using a CMOS inverter) between the points a and b put a resistor. At frequencies of 32 kHz, this is 10 - 30 Mega ohms. And frequencies greater than 1 megahertz are approximately 100kΩ -1MgaOhm.
 

Thread Starter

Ngô Đình Nhân

Joined Jan 8, 2017
45
Usually (when using a CMOS inverter) between the points a and b put a resistor. At frequencies of 32 kHz, this is 10 - 30 Mega ohms. And frequencies greater than 1 megahertz are approximately 100kΩ -1MgaOhm.
Hello Bordodynov

Thanks for reply.
In a real circuit, I had areadt put a 2.2Meg Resistor between a and b.

But my problem is that i need a DC offset at a or b as my draw in image.

So, do you have any recommendations?
 

Bordodynov

Joined May 20, 2015
2,468
What kind of inverter are you using? Detailed information increases the opportunity to help you. But I can say that the resistor stabilizes the DC operating point. At the input, a DC offset is supported equal to the inverter switching threshold.
2018-10-17_14-28-42.png
 

fernandopv

Joined Oct 20, 2018
10
Hi all

I am doing a Pierce Oscillator with a quartz crystal. But I don't know how I can create a DC offset at point (a) or (b) in that circuit ?

Please see me attached image for more clear.

So, does any give me some recommendation ? I really appreciate your helps.
Perhaps you need to add this: (it will work with senoids too after some cycles)
 
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