How to calculate the flux in the two connection wire in magnetic circuit ?

Thread Starter

Reject123

Joined Mar 1, 2020
3
Please help me solve this homework, im stuck with it
I think there will be 4 reluctance in this circuit, 1 in the left wire , 2 in the top , 3 in the right wire and 4 in the bot, i dont know whether it's right or wrong , so help me please.
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Jony130

Joined Feb 17, 2009
5,170
No, you have only one reluctance in this case. So try to calculate the reluctance base on the core dimensions given to you. Can you do it?
 

Thread Starter

Reject123

Joined Mar 1, 2020
3
No, you have only one reluctance in this case. So try to calculate the reluctance base on the core dimensions given to you. Can you do it?
According to some previous topic that i have learnt , If a magnetic circuit has 1 wrapped then will have 2 reluctances which is reluctance of the iron core ( assume it is ferromagnetic core), and another one is recluctance in the wrapped, so i dont understand what your meant ? :(
Can you explain more ?
 

Jony130

Joined Feb 17, 2009
5,170
You understand it wrongly. In your example, you have only one path for magnetic flux to "flow". Hence only one reluctance value.

R = le/(μ*Ae)

le - Effective magnetic path length
Ae - Effective core area
μ = μo * μr
 

Thread Starter

Reject123

Joined Mar 1, 2020
3
You understand it wrongly. In your example, you have only one path for magnetic flux to "flow". Hence only one reluctance value.

R = le/(μ*Ae)

le - Effective magnetic path length
Ae - Effective core area
μ = μo * μr
Thank you very much, I get it now :D
 
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