Hi guys, I am new here.
I don't quite understand the material about the Millman's theorem presented on the Online Textbook of All About Circuit.
http://www.allaboutcircuits.com/vol_1/chpt_10/6.html
Here is an example given on the page:
Up till here, my understanding of the theorem is:
Potential Difference across all branches = Total Current into the branches / Equivalent Conductance of all branches together
Whereas the
Total Current into the branches = Sum of Current flowing in each branch
Current flowing in a branch = EBi/Ri, i=1,2,3...
However, in the next step, the emf of the battery is directly plugged into the EBi, which I don't understand why.
Why the current of a branch can be calculated as if it is separated (see attachment: 001.png)?
Did I missed something? Please help.
Thank you.
I don't quite understand the material about the Millman's theorem presented on the Online Textbook of All About Circuit.
http://www.allaboutcircuits.com/vol_1/chpt_10/6.html
Here is an example given on the page:
Up till here, my understanding of the theorem is:
Potential Difference across all branches = Total Current into the branches / Equivalent Conductance of all branches together
Whereas the
Total Current into the branches = Sum of Current flowing in each branch
Current flowing in a branch = EBi/Ri, i=1,2,3...
However, in the next step, the emf of the battery is directly plugged into the EBi, which I don't understand why.
Why the current of a branch can be calculated as if it is separated (see attachment: 001.png)?
Did I missed something? Please help.
Thank you.
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