please see attached pic. The solution to this was rather lengthy using KVL etc.
Is there a simpler way to get V2?
thanks
Is there a simpler way to get V2?
thanks
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That's not KVL, it is KCL.sorry, here is the solution provided (see attached). Just wondering if there's a faster/easier way.
thanks
The solution shown uses KCL (not KVL) and shows the steps involved in getting two equations in two unknowns in gory detail, which is what makes it appear long. With a bit of practice and using a formalized way of applying KCL known as Nodal Analysis, you can write the two equations by inspection as:sorry, here is the solution provided (see attached). Just wondering if there's a faster/easier way.
thanks
Sure.thank you so much. Can you please exlplain the source transformation method a bit further..
I don't understand how the 2A source becomes 4/3 A in parallel with a 6ohm resistor.
I appreciate your help
Yes, you can add them because each one is injecting current into the top node. If they were voltage sources you would most definitely NOT add them. In fact, unless they have the exact same voltage output, two voltage sources in parallel result in an undefined voltage on that node because the two voltage sources will fight each other. In the real world voltage sources all have some amount of series resistance which will determine the resulting voltage. But even in the real world, if the two sources differ by too much voltage and the series resistances are too small, the result will be such a large current flow that something bad will happen, ranging from overheated and damaged components to a catastrophic and potentially dangerous explosion.thank you WBahn I understand now how you get the simplified source transform circuit. (attached sketch)
The last question I have is.. you are able to simply add up those current sources? If they were voltage sources, would you still be able to add them?
Thanks!
by Robert Keim
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