determine the value of R2 and the total power dissipated by the load resistors.

Since Voltage is the same in parallel, I used Ir3 x R3 and got voltage of 108V. Ir1= 108V/15K Ohm = 7.2mA. Itotal = 13.2mA. 13.2mA-2.3mA-7.9mA= 3.7mA. R2= 108V/3.7mA= 29k Ohm. Power is V(squared)/Rtotal. Rtotal= reciprocal of sum of resistors. Power equals 1.4 Watts

 

Do the work first then post your answer. We're not a homework service.

 

blue room, wasn't asking for answer, was looking for guidance. So your ideaology that you are the enforcer of this website is not appreciated.

 

Guess you didn't read the sticky.

The Homework Help Forum is not a free homework service; we are here to help your understanding, but fully expect the users of this forum to dictate the course of their own learning.

When posting a request for homework/coursework/assignment help, you must provide details of your attempts at the questions. Any thread that just posts up a copy of the questions without any attempts on the part of the opening poster will be directed to this thread and will be given 48 hours to satisfy the requirements detailed within. Help us, help you.

 

That's the answer I came up with.

Good job in figuring that out systematically.
You seem to understand the basic theorems KVL and KCL and ohms law, quite well.