Help is needed! - Design of Class-C RF PA using ADS

Thread Starter

Waseem Dabbas

Joined Aug 15, 2018
5
Hello everyone,

I have managed to design a Class-A amplifier at 1 GHz (see attached) using ADS
Now, I have to drive it harder to move it from class-A to class-C (From linear mode to non-linear)
I did some modifications on the circuit but I am not quite sure about the correct steps!
I have to investigate into how the resonant circuit affects the output power, and then the efficiency as a function of a conduction angle and so on.

Is there anybody can help with the right starting off steps please?
N.B: I am still new to an RF design world, so please make it simple as much as you can

Your help is much appreciated
 

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Thread Starter

Waseem Dabbas

Joined Aug 15, 2018
5
Hello,

How much input power would you need to activate the transistor?

Bertus
Hi Bertus

Thank you for your reply.
I'm using BFP740F transistor and I don't know the actual value (I didn't find in the datasheet :( )
I have calculated L and C values of the tank circuit to be resonating at 1 GHz but I am getting this output current waveform and I don't know what do I need to do!!!
Please see attached screenshots of what I have got so far
Also please be patient as I am don't have a previous experience in RF
Thank you for your understanding
 

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bertus

Joined Apr 5, 2008
22,943
Hello,

The datasheet only shows the Class A characteristics of the transistor.
For Class C, there is no base current.
To activate the transistor, there should be enough power on the input to have the transistor activated (create a base current).
This usualy happens when the input voltage is over the B-E limit voltage.

Have a look at some RF power transistors, how those schematics and characteristics are used.

Have a look at the attached PDF about Class C.

Bertus
 

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Thread Starter

Waseem Dabbas

Joined Aug 15, 2018
5
Hello Betrus,

In order to find the optimal value for tank circuit component, I have to calculate the Q factor first which can be calculated as Q=Fc/BW
Next, the source and load resistance are combined to determine the total parallel resistance of the circuit using Rp= Zs.Zl/Zs+Zl
After that the parallel reactance could be determined using Xp=Rp/Q
Finally, by substituting in L=Xp/w and C=1/w.Xp we can get the L and C value
The problem is in determining the source and load impedances as I thought they could be calculated using the input and output conjugate (as you can see in the attached screenshot) and I'm really confused!
Could you please advise?
Thanks
 

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