so, the H parameter , I set V2, I1 in the left side is also correct? and in Transmission para I set plus sign instead of minus is also correct? they give the same result , right???IIRC, all of the basic parameter definitions {z, y, h, and g} have one input and one output quantity on each side.
For the transmission parameters, I think the negative sign on I2 stems from the current on one side must be the negative of the current on the other. But, again IIRC, some authors don't define it this way.
Huh?so, the H parameter , I set V2, I1 in the left side is also correct? and in Transmission para I set plus sign instead of minus is also correct? they give the same result , right???
For example: the left side of original equations of Hybrid para is V1 and I2 , now if I change into V2 and I1 then the result is the same with original equation????Huh?
You can't just go changing them however you want and expect to get the same result.
Look at the subscripts.
On the left, you need something from the input on the top and something from the output on the bottom.
On the right, you will get something from the input on the top and something from the output on the bottom.
As for the transmission parameters, you need to use them as they are defined and be consistent. If you use a text that defines them differently, then the definitions are different and you need to use them according to those definition.
Transmission parameters usually do not have subscripts because they do not follow the subscript convention. This is why they are usually called ABCD parameters.
No!For example: the left side of original equations of Hybrid para is V1 and I2 , now if I change into V2 and I1 then the result is the same with original equation????
It is hard to full absord what you mean. I try it later. Thank youNo!
The values of the parameters are based on which quantities are used. You can't just use an input where an output was and expect to get the same results.
Think about a very simple case of a network where the output voltage is 1/10 of the input voltage. Do you really think that it makes sense that you can swap input and output and all of a sudden have the input voltage be 1/10 of the output voltage?
Hi,The book says the definition of H para View attachment 337639, my question why V1 and I2 set on the left of equation not V2 , I1 on the left of equations
and the def of Transmission para View attachment 337641, why the minus is used in the equation not the plus sign? thank you all
Can you please simplify what you mean or visually compare to something easy to understand about H para? about Transmissions parameter I understand why they normally use the minuss sign because the output often is considerd to go out the circuit.Hi,
To start with the h-parameters, take a T network made with three resistors and do a circuit analysis keeping in mind that you want to define the following parameters:
1. Short-circuit input impedance.
2. Short-circuit current gain.
3. Open-circuit reverse voltage.
4. Open-circuit output admittance.
Oh and I1 and I2 both point into the network.
When you define these parameters so that you can do measurements on that T network (or any other two port network) you end up with the equations you have shown with the h-parameters.
You don't have to use these, there are other types. For example:
1. Admittance parameters
2. Impedance parameters
You can make your own by converting them, then you'll end up with different parameters. Then you'll have to correlate that to physical measurements you make on the network like those four outlined above. If you can't then they will be worthless I think. You might end up with some sort of inverse parameters that can be equated to the h-parameters.
You could try making I1 and I2 point differently I guess and see what you end up with.
I understand the reason for your question though, I think it is because we normally want to calculate the output from the input conditions, while V1 on the left seems to contradict that basic intuition.
However, if you want to put V2 on the left, then you'd have to define a constant equal to:
hxx=h11/h12
and now I think it might be hard to relate that to a direct physical measurement that is relatively easy to make and maybe understandable. We'd have to call it something, and it seems like it would have to be called the short circuit input impedance over the open circuit reverse voltage, which would be 1/amperes which I don't think we have a unit for (maybe somewhere). "Short-circuit-input-impedance-open-circuit-reverse-voltage reciprocal-of-current?". Have fun measuring that
Thus, the forms of the two equations may be written that way so that we can make the required measurements in real life without too much trouble, and then calculate everything, while keeping the forms in a neat and orderly manner. Remember you can always just solve for V2 given those equations.
Another aspect is that network equations are hardly every used alone so they would be mixed with other equations anyway. Keeping the forms as simple as they are is probably the best way.
See what you can come up with and see if you can find a reason to do it another way, other than the other well-known ways of doing this.
Yes I can understand the minus sign, that must be right. The h params are always into the network.Can you please simplify what you mean or visually compare to something easy to understand about H para? about Transmissions parameter I understand why they normally use the minuss sign because the output often is considerd to go out the circuit.
Hello again,Can you please simplify what you mean or visually compare to something easy to understand about H para? about Transmissions parameter I understand why they normally use the minuss sign because the output often is considerd to go out the circuit.
It would be worth your while to study: https://en.wikipedia.org/wiki/Two-port_networkThe book says the definition of H para View attachment 337639, my question why V1 and I2 set on the left of equation not V2 , I1 on the left of equations
and the def of Transmission para View attachment 337641, why the minus is used in the equation not the plus sign? thank you all
I realized that I forgot to mention one important point regarding your question.Can you please simplify what you mean or visually compare to something easy to understand about H para? about Transmissions parameter I understand why they normally use the minuss sign because the output often is considerd to go out the circuit.