# Frequency response 1st order

#### Montop

Joined Oct 29, 2015
3

I am having a bit of trouble trying to figure this out. The equation I come up with keeps canceling Omega out.

Attempt:

Converting the circuit to the frequency domain the capacitor becomes $$\frac{4}{j \omega}$$.

I then used a current divider to find $$\underline Y(j \omega) = \underline u(j \omega) * \frac{(2+(\frac{4}{j \omega}))}{6+(2+(\frac{4}{j \omega}))}$$

Simplifying this I get the frequency response to be $$\frac{1}{2}$$. I am fairly certain that his is not correct.

#### RBR1317

Joined Nov 13, 2010
691
I am fairly certain that his is not correct.
I would tend to agree since Y=U*Z, where Z is the parallel combination of the R & RC branches.