# Frequency response 1st order

Discussion in 'Homework Help' started by Montop, Nov 13, 2015.

1. ### Montop Thread Starter New Member

Oct 29, 2015
3
0

I am having a bit of trouble trying to figure this out. The equation I come up with keeps canceling Omega out.

Attempt:

Converting the circuit to the frequency domain the capacitor becomes $\frac{4}{j \omega}$.

I then used a current divider to find $\underline Y(j \omega) = \underline u(j \omega) * \frac{(2+(\frac{4}{j \omega}))}{6+(2+(\frac{4}{j \omega}))}$

Simplifying this I get the frequency response to be $\frac{1}{2}$. I am fairly certain that his is not correct.

2. ### RBR1317 Senior Member

Nov 13, 2010
472
90
I would tend to agree since Y=U*Z, where Z is the parallel combination of the R & RC branches.