I agree with Ron H, in that you do need to study this on your own using on line references and books. I'll look around to make some recommendations later.
Your questions could generate very detailed answers and you may very well get different opinions from different people. I don't think I can do justice to the answers you need, in full detail, but I can try to make a passing comment about each of your questions.
Q1 Your confusion about common mode and differential mode is likely the result of not approaching the subject in a proper and detailed way. The course and the book are what they are, and you are limited by them. I've always believed that sometimes a simplified approach is harder than a full and proper headlong dive into the details. Ron's comments about tracking down good references and learning is right on here.
Q2 Don't worry about how to do it practically because you won't need to. If by some odd chance you ever need to, it will happen long after you know the answer to your question.
Q3 Yes, the current is consumed in the sense that there is a voltage and current that determines power, which is consumed. It's a small power that you don't need to ever worry about. I guess it is called bias current because it is needed to drive or bias the input stage transistors. Without a DC path on the inputs, the OPAMP won't operate properly.
Q4 This gets back to common mode and differential mode issues. You need to learn how common mode and differential mode signals are defined, and how the OPAMP behaves to these two types of signals. Note that any input signal can be represented as a sum of a differential mode signal plus a common mode signal.
Q5 Don't worry about measuring this. It's a circuit model. The values are determined such that they best agree with measurements. Knowledge of the actual circuit design and creative measurements can be used to get a good model, but this is far beyond the level you are at.
Q6 The voltage offset from the input current is only one contribution to the total offset voltage.
Q7 Rise time and bandwidth are always related and are basically indications of the same information in both the time domain and frequency domain. The relation between the two is determined by Fourier analysis and linear system theory. In a nutshell, high bandwidth gives fast rise time for a step input. Low bandwidth gives slow rise time for a step input.
Note that a step is defined to be something that starts at zero and switches instantly to another value at time zero, and then stays there for all time afterwards. A pulse is not a step because a pulse eventually goes back down to zero.
Q8 Yes
Your questions could generate very detailed answers and you may very well get different opinions from different people. I don't think I can do justice to the answers you need, in full detail, but I can try to make a passing comment about each of your questions.
Q1 Your confusion about common mode and differential mode is likely the result of not approaching the subject in a proper and detailed way. The course and the book are what they are, and you are limited by them. I've always believed that sometimes a simplified approach is harder than a full and proper headlong dive into the details. Ron's comments about tracking down good references and learning is right on here.
Q2 Don't worry about how to do it practically because you won't need to. If by some odd chance you ever need to, it will happen long after you know the answer to your question.
Q3 Yes, the current is consumed in the sense that there is a voltage and current that determines power, which is consumed. It's a small power that you don't need to ever worry about. I guess it is called bias current because it is needed to drive or bias the input stage transistors. Without a DC path on the inputs, the OPAMP won't operate properly.
Q4 This gets back to common mode and differential mode issues. You need to learn how common mode and differential mode signals are defined, and how the OPAMP behaves to these two types of signals. Note that any input signal can be represented as a sum of a differential mode signal plus a common mode signal.
Q5 Don't worry about measuring this. It's a circuit model. The values are determined such that they best agree with measurements. Knowledge of the actual circuit design and creative measurements can be used to get a good model, but this is far beyond the level you are at.
Q6 The voltage offset from the input current is only one contribution to the total offset voltage.
Q7 Rise time and bandwidth are always related and are basically indications of the same information in both the time domain and frequency domain. The relation between the two is determined by Fourier analysis and linear system theory. In a nutshell, high bandwidth gives fast rise time for a step input. Low bandwidth gives slow rise time for a step input.
Note that a step is defined to be something that starts at zero and switches instantly to another value at time zero, and then stays there for all time afterwards. A pulse is not a step because a pulse eventually goes back down to zero.
Q8 Yes