Thanks, would it be possible to bypass the other switches and make this work?The signal output from the amplifier will turn on Q1 to activate the solenoid.
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Yes if that would be the easiest way to make it work. I don't have a lot of experience with electronics but I can put it together if I know the right components. If there is a module that would work please let me know.Seems overkill.
You have the amp board currently so would you prefer a relay module driven by the amp board to activate the solenoid?
12v would probably be best but I could make either 3v with 2 D cells or 4v with lipo batteries. The solenoid came from a unit that used 3v and that's what I tested it with which worked fine. I got such a slight signal when I used 3v on the amp I decided to try 12v and was much better but still not enough to drive the solenoid. As long as there's 3v and enough amps (.22) going to the solenoid I believe it should work. If it's easier to use 3v battery supply that's fine. I appreciate your help.You mentioned a 12 volt battery, is that going to be the power source for the amp board and solenoid?
What other supplies are available and/or how do you want to power this project?
All I have is a multimeter, it I was able to get it up to 3v briefly with a lighter but couldn't keep it there. If I put my finger on both the sensor and the burner it will stay at 3v. I can adjust the gain on the board to get more.How much voltage can you get out the amp without the solenoid connected using the 12 volt battery.
This will help knowing the best way to do this.
No, less with lighterMeaning you can use your finger instead of the lighter to get a steady output voltage?
Can you get more voltage output using the lighter?
No I don't plan to use my finger, if the burner won't start with the lighter I was going to use a momentary push button switch.Is your plan to use your finger to activate the solenoid?
Will you have time to remove your finger before the burner kicks on?
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3vSounds better.
So the operation is to hold the momentary switch long enough for the burner to kick on.
How much voltage is produced when that happens?
yes, that would open the solenoid 0.22 amps, if I had it configured correctly shouldn't it be able to open the solenoid with the lighter and keep it open as long as the burner is lite?Only 3 volts max output when the burner is fully on?
with 12v connected to the amp still less than 3v. there is not much difference weather the burner or a lighter is on the sensor. There isn't going to be a huge increase in voltage when the burner comes on.I'm asking how much voltage is coming out of the amp when the burner is fully on.