Hi guys, can anyone please explain what will be the output for this circuit & its working...! Sorry, but please be as quick as possible as i need it urgently.
thanks in advance..!

 

Hi guys, can anyone please explain what will be the output for this circuit & its working...! Sorry, but please be as quick as possible as i need it urgently.
thanks in advance..!

View attachment 7020

It's a clamp circuit. It will offset your input signal downwards by about 3.5 volts., with no small amount of distortion.

eric

 

It will clip the output voltage at about +5.7V.

 

This is what i came up with 2..but the answer given in the book is

The explaination given for this answer is that

Va = [10kohm/(10+10)] * 5sinwt = 5sinwt

w = frequency (rad/sec).
Va is the voltage at the anode of the diode.

Since maximum voltage at point A may be 5V, hence voltage across the diode always will be less than or equal to zero.
 So it willbe reversed always.

I couldnt understand this explaination...is it incorrect or is there some part of the problem that i overlooked??

Please point out the solution and Thanks for your quick replies, really appreciate it..!

 

Yes, the book is right. I missed that both resistors are 10K (form a voltage divider) and the maximum output voltage is +-5V. Thus the diode will never conduct.

 

Thanks a lot guys for the help & especially mik3...solved the problem for me!!
cheers