# Explanation needed for circuit!!

Discussion in 'General Electronics Chat' started by mechas, Feb 4, 2009.

1. ### mechas Thread Starter New Member

Oct 23, 2008
3
0
Hi guys, can anyone please explain what will be the output for this circuit & its working...! Sorry, but please be as quick as possible as i need it urgently.

2. ### KL7AJ AAC Fanatic!

Nov 4, 2008
2,177
407

It's a clamp circuit. It will offset your input signal downwards by about 3.5 volts., with no small amount of distortion.

eric

3. ### mik3 Senior Member

Feb 4, 2008
4,846
69
It will clip the output voltage at about +5.7V.

4. ### mechas Thread Starter New Member

Oct 23, 2008
3
0
This is what i came up with 2..but the answer given in the book is

The explaination given for this answer is that
Code ( (Unknown Language)):
1.
2. V[SIZE="1"]a[/SIZE] = [10kohm/(10+10)] * 5sinwt = 5sinwt
3.
5. V[SIZE="1"]a[/SIZE] is the voltage at the anode of the diode.
6.
7. Since maximum voltage at point A may be 5V, hence voltage across the diode always will be less than or equal to zero.
8.  So it willbe reversed always.
9.
I couldnt understand this explaination...is it incorrect or is there some part of the problem that i overlooked??

Please point out the solution and Thanks for your quick replies, really appreciate it..!

5. ### mik3 Senior Member

Feb 4, 2008
4,846
69
Yes, the book is right. I missed that both resistors are 10K (form a voltage divider) and the maximum output voltage is +-5V. Thus the diode will never conduct.

6. ### mechas Thread Starter New Member

Oct 23, 2008
3
0
Thanks a lot guys for the help & especially mik3...solved the problem for me!!
cheers