Hi!
I have what I thought was a success with a few weeks of operation, but failed
This part of the system uses a 4043B latch(Vdd 5V) to trigger a IRL540 mosfet to operate a solenoid valve that has a 3-4 ohm resistance and a 12V supply. Most of the time, the solenoid will only need to operate for a few minutes every 24 hours or so, but would like it to be able to operate for an hour or so from time to time.
It appears the failure was in the 4043B. For the conditions Q should have been high but appeared to be open.. I was able to trigger the mosfet by simply jumpering 5V to the gate. This led me to review the datasheet for the 4043 and question if I am requesting too much power from it to trigger the mosfet.
If I understand the datasheet for the 4043 correctly, Ioh would be the maximum current that can be supplied by the Q pin to the mosfet gate? From there it appears the maximum current this chip can supply to the mosfet is at worst 0.3mA, and at best 1mA??? My 1K pull down is going to pull 5mA plus the requirements of the mosfet's gate. Which, again, if I understand the datasheet correctly is more than the 4043 can supply.
So... am I understanding the datasheet to this point correctly?
If so, if I replace the 1K resistor with something like a 20K, would the system be reliable since now the current through the track would be 0.25mA? Is the 20K enough to ensure stability?
Is the pull down even necessary? On the datasheet it listed a sinking current. At first, I assumed when Q was not high it was floating(hence the pull down), but maybe without a pull down the 4043 has enough sinking current to prevent the mosfet from activating without a pull down?
Thanks for the help! Prototyped this on a solderable breadboard a few months ago, and after everything seemed good had PCB's made and ordered parts for a less hokey version. Was planning to build the boards tomorrow before I go out of town for a while, then saw the failure tonight. .
I have what I thought was a success with a few weeks of operation, but failed
This part of the system uses a 4043B latch(Vdd 5V) to trigger a IRL540 mosfet to operate a solenoid valve that has a 3-4 ohm resistance and a 12V supply. Most of the time, the solenoid will only need to operate for a few minutes every 24 hours or so, but would like it to be able to operate for an hour or so from time to time.
It appears the failure was in the 4043B. For the conditions Q should have been high but appeared to be open.. I was able to trigger the mosfet by simply jumpering 5V to the gate. This led me to review the datasheet for the 4043 and question if I am requesting too much power from it to trigger the mosfet.
If I understand the datasheet for the 4043 correctly, Ioh would be the maximum current that can be supplied by the Q pin to the mosfet gate? From there it appears the maximum current this chip can supply to the mosfet is at worst 0.3mA, and at best 1mA??? My 1K pull down is going to pull 5mA plus the requirements of the mosfet's gate. Which, again, if I understand the datasheet correctly is more than the 4043 can supply.
So... am I understanding the datasheet to this point correctly?
If so, if I replace the 1K resistor with something like a 20K, would the system be reliable since now the current through the track would be 0.25mA? Is the 20K enough to ensure stability?
Is the pull down even necessary? On the datasheet it listed a sinking current. At first, I assumed when Q was not high it was floating(hence the pull down), but maybe without a pull down the 4043 has enough sinking current to prevent the mosfet from activating without a pull down?
Thanks for the help! Prototyped this on a solderable breadboard a few months ago, and after everything seemed good had PCB's made and ordered parts for a less hokey version. Was planning to build the boards tomorrow before I go out of town for a while, then saw the failure tonight. .
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