- Joined Dec 18, 2020
The definitive way would be to measure it. You could use capacitor voltage, but that should be a conservative voltage.Sorry, my English must be sub-par as I have not explained my dilemma well. I do not know the secondary voltage and current so I need to know alternative strategies to determine this.
Can you please give me some guidance on how I may be able to determine the secondary voltage. For example, can I extrapolate by looking at the value of capacitors in the circuit after the diode?
No, that diode is wayyyy too slow as a SMPS rectifier like D8, D10 or D11. The diodes must be fast recovery.A 1n5400, a 3A 50V diode should work fine in the applications.
This is a simple linear regulator circuit(s), not SMPS. Any 1N540x diode should work just fine, allowing up to 3A current to feed linear regulators that are limited to 1 or 1.5A themselves. In fact, some regulators in schematic at the "L" series, 100mA at most so a standard 1N400x series will do.No, that diode is wayyyy too slow as a SMPS rectifier like D8, D10 or D11. The diodes must be fast recovery.
One problem is Japan offers 1.5A and 2A rectifier diodes but North American semi's only offer 1A and 3A.
It would be UF5402 for a fast 3A part but these have fat leads 0.9mm and might not fit the PC board. BYV26A or SF4002 is closest to D11 (sintered glass package) 1A 200PIV fast recovery.
You can just scrub/wash the parts too, they don't look corroded.
Thanks for the response. I have a a selection of fast recovery diodes in my stocks anyway so it is no issue to put these on the board. I am thinking that for the smaller diodes e.g. D07 that a FR207 might be the closest match. I'll replace the 1n5400 at D8 with a UF5402.Sega G-Loc has an SMPS, which means fast-recovery rectifier diodes are required.
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by Jake Hertz
by Jake Hertz
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