Yes I need to show what happens for different values of V_inBy defining Vin. All you show is that it is 1 kHz sine wave. If the sine wave never exceed 0.7 volts, then D3 is always off and Vout is always zero. See how simple this is?
Also D3 has 25 volt battery on the cathode end, which means you will need a lot more than 0.7 volts to turn it on.
What is the range of Vin?Yes I need to show what happens for different values of V_in
The answer is:What is the range of Vin?
Not if it's a sinusoidal source.The answer is:
Vin<50V Vout=50V
50V<Vin<100V Vout=Vin
Vin>100V Vout=100V
Think of those diodes as perfect diodes (Vfwd=0v).How Should I start looking at this?
Thanks, how did you recognized that when Vin>50v "Vab is clamped to Vin"?Think of those diodes as perfect diodes (Vfwd=0v).
The current through R2+R3 is (100v-25v)/300k=.25ma. So the voltage drop over R2 is .25ma * 200k = 50v.
That means the voltage on top of R3, where the two diodes' cathodes meet, is 25v+25v=50v.
That means that when Vin < 50v, D3 is not forward-conducting and Vin is not in the circuit. so Vab=50v when Vin < 50v.
As Vin goes over 50v, D3 starts to conduct, and Vab is clamped to Vin. Vab = Vin when Vin > 50v.
That relationship breaks down when Vin goes over 100v. In that case, D2 is not conducting and no current flows through R2. So Vab=100v - 0ma * 200k = 100v.
To summarize:
Vin < 50v, Vab = 50v;
50v<Vin<100v, Vab = Vin;
100v < Vin, Vab = 100v
In that case, both diodes are conducting and both Vin and the 100v source are powering the 25v source. However, Vin does so without any resistance soo it overwhelms.how did you recognized that when Vin>50v "Vab is clamped to Vin"?
by Duane Benson
by Duane Benson
by Aaron Carman
by Aaron Carman