1. Leave the junction of the voltage sources grounded so they behave correctly as AC voltage generators.
As was already mentioned a few times, the voltage sources should not be grounded. If you do that anyway, hundreds of amps are driven through the now redundant bottom diodes during the negative half wave(s) and you are left with half wave rectification.1. Leave the junction of the voltage sources grounded so they behave correctly as AC voltage generators.
The line-to-line RMS voltage VL_rms is already off which leads to the wrong average DC output voltage Vdc. Only 48V DC left? How or where are ~5.8V "lost"?VAC input:
VL_rms = 39.9
Convert VAC to Peak:
VL_pk = VL_rms*sqrt(2)
Compute VDC out:
Vdc = ((3*sqrt(3))/pi) * (VLpeak/sqrt(3)) = 53.884-(diode drops) = ~48VDC (won't be exact)
No. The diodes, filter and load should be referenced to "neutral" instead of simulator ground.As was already mentioned a few times, the voltage sources should not be grounded. If you do that anyway, hundreds of amps are driven through the now redundant bottom diodes during the negative half wave(s) and you are left with half wave rectification.
Compute VDC out:The line-to-line RMS voltage VL_rms is already off which leads to the wrong average DC output voltage Vdc. Only 48V DC left? How or where are ~5.8V "lost"?
48 V_dc with 30 mV_pk-pk, 90 Hz ripples:The whole point of this is to produce 48vdc out with some ripple into a 1305 ohm load (load acting as an SMPS).
I don't know what the filter is supposed to represent.

...then why are the voltage sources connected to the same GND as the load? Neutral is not the same as load GND.No. The diodes, filter and load should be referenced to "neutral" instead of simulator ground.
My point was that the 53.884V is not correct because VL_rms is already wrong. The sudden jump to 48V DC is still unclear.Compute VDC out:
Vdc = ((3*sqrt(3))/pi) * (VLpeak/sqrt(3)) = 53.884-(diode drops) = ~48VDC (won't be exact)
Do you really mean a generator rather than motor? A 15Hz 8 pole synchronous machine will run at 225RPM (RPM=120*f / POLES)Hi!
I’m simulating a three-phase rectifier with diodes and an R-78HE5.0-0.3 DC-DC converter in LTSpice.
The three sine waves come from a three-phase motor which I assume runs at 15 Hz, so with 8 pole pairs that’s approximately 111 rpm (this is just an example)
---------------------------------------------1---------------------------------------------
Can I simulate the DC-DC converter by replacing it with an equivalent resistor?
I’m afraid I might be doing something wrong when setting up the three input generators


Hi, and thanks for the reply and the simulation.Do you really mean a generator rather than motor? A 15Hz 8 pole synchronous machine will run at 225RPM (RPM=120*f / POLES)
Machines are rated with line to line (L-L) RMS voltage and Line RMS current no matter how the windings are connected. The output terminals are T1, T2, & T3. If the other end of the windings are brought out they will be T4, T5 & T6.
Others have pointed out that the generator neutral must not be connected to the common (either pole) of a full wave rectifier or to any other node in the circuit. Generally, power rectifiers are fed from a dedicated transformer that is either a delta or wye connected and is ungrounded. For actual physical equipment the actual circuit ground is somewhere after the rectifier. Placement of the ground terminal can make making measurements difficult since Spice uses circuit ground as the reference.
A generalized 3 phase generator using V peak and f as input parameters is used in the circuit below. I've also generalized the output filter. The frequency was picked to make the important places on the 3 phase waveform line up with the grid.
Since the generator neutral can't be connected to any part of the circuit, it isn't modeled. You can experiment with different filter arrangements by changing the appropriate param values.
You may need a better DC-DC converter model since some filter settings may interact with the switching devices in the converter. The input phase currents are nasty and will produce all sorts of harmonics that will cause increases losses in a real rotating machine or transformer.
First time posting images so apologies if they're too big/small/wrong format, etc.
View attachment 370474
View attachment 370475
One more question: why are C1 and L2 in the filter you included only 1 pF and 1 nF, respectively? Are they almost negligible in the circuit?Do you really mean a generator rather than motor? A 15Hz 8 pole synchronous machine will run at 225RPM (RPM=120*f / POLES)
Machines are rated with line to line (L-L) RMS voltage and Line RMS current no matter how the windings are connected. The output terminals are T1, T2, & T3. If the other end of the windings are brought out they will be T4, T5 & T6.
Others have pointed out that the generator neutral must not be connected to the common (either pole) of a full wave rectifier or to any other node in the circuit. Generally, power rectifiers are fed from a dedicated transformer that is either a delta or wye connected and is ungrounded. For actual physical equipment the actual circuit ground is somewhere after the rectifier. Placement of the ground terminal can make making measurements difficult since Spice uses circuit ground as the reference.
A generalized 3 phase generator using V peak and f as input parameters is used in the circuit below. I've also generalized the output filter. The frequency was picked to make the important places on the 3 phase waveform line up with the grid.
Since the generator neutral can't be connected to any part of the circuit, it isn't modeled. You can experiment with different filter arrangements by changing the appropriate param values.
You may need a better DC-DC converter model since some filter settings may interact with the switching devices in the converter. The input phase currents are nasty and will produce all sorts of harmonics that will cause increases losses in a real rotating machine or transformer.
First time posting images so apologies if they're too big/small/wrong format, etc.
View attachment 370474
View attachment 370475
Stability of voltage after filter is the same as stability of input voltage.I would also like to understand if a possible filter could create stability for the switching power supply that I use.
CALCULATOROne more question: why are C1 and L2 in the filter you included only 1 pF and 1 nF, respectively? Are they almost negligible in the circuit?
If I'm right, then it's a simple low-pass filter consisting of C2 and L1

Thanks, but in the filter di @Fred_47 , however, there's still a capacitor missing at the end:Stability of voltage after filter is the same as stability of input voltage.
CALCULATOR
View attachment 370518

It is impossible - "no capacitor", because any load has its own capacitance.Thanks, but in the filter di @Fred_47 , however, there's still a capacitor missing at the end:
I didn't intend the L C arrangement to be any particular filter.One more question: why are C1 and L2 in the filter you included only 1 pF and 1 nF, respectively? Are they almost negligible in the circuit?
My hunch is that the DC-DC converter has a similar topology to a SMPS. I would model at least the input switching components or some sort of stand in that includes the input filter and a PWM load to introduce the high frequency pulsating current and /or voltage.When you say we need better DC-DC modeling, do you happen to know how to do it?
The only thing I've thought of is trying different resistor values, simulating a current draw that varies over time.

Hi, I have this error in yout ltspice file:3-phase voltage sources with Isolated or grounded neutral work identically,
but rest of circuit, after diode bridge, should be grounded for simulation:
View attachment 370372View attachment 370373

Why didn’t you use three generators arranged in this way in your simulation?Do you really mean a generator rather than motor? A 15Hz 8 pole synchronous machine will run at 225RPM (RPM=120*f / POLES)
Machines are rated with line to line (L-L) RMS voltage and Line RMS current no matter how the windings are connected. The output terminals are T1, T2, & T3. If the other end of the windings are brought out they will be T4, T5 & T6.
Others have pointed out that the generator neutral must not be connected to the common (either pole) of a full wave rectifier or to any other node in the circuit. Generally, power rectifiers are fed from a dedicated transformer that is either a delta or wye connected and is ungrounded. For actual physical equipment the actual circuit ground is somewhere after the rectifier. Placement of the ground terminal can make making measurements difficult since Spice uses circuit ground as the reference.
A generalized 3 phase generator using V peak and f as input parameters is used in the circuit below. I've also generalized the output filter. The frequency was picked to make the important places on the 3 phase waveform line up with the grid.
Since the generator neutral can't be connected to any part of the circuit, it isn't modeled. You can experiment with different filter arrangements by changing the appropriate param values.
You may need a better DC-DC converter model since some filter settings may interact with the switching devices in the converter. The input phase currents are nasty and will produce all sorts of harmonics that will cause increases losses in a real rotating machine or transformer.
First time posting images so apologies if they're too big/small/wrong format, etc.
View attachment 370474
View attachment 370475

Switch SPICE solver from Normal to Alternate mode:Hi, I have this error in yout ltspice file: