Hello ,I have built a PID controller which is connected to differential driver by the manuals below.
The PID is single ended while the driver is differential so I connected the two using converter.
The key component is the integrator.
I want that the driver to create a current on the load so It will be following the integrator output signal.
However as you can see that as integrator output rises the driver current saturated as some point .
Is there a way to fix the driver so it wont sature so quickly?
Ltspice files are attached.

https://www.analog.com/en/resources...ne-driver-receiver-design-guide-part-two.html
https://www.analog.com/en/resources...n-single-ended-to-differential-converter.html

 

Reduce the gain of the driver.

 

There are so many resistors in the drive circuit ,
How do you reccomend to reduce the gain ?

 

How do you reccomend to reduce the gain ?

Increase the value of R1.

 

Hello Crutschow, worked perfectly as shown below..
Could you please show the mathematical logic behind this intuition,so I could learn the logic behind it?
Thanks.

 

The voltage gain is determined by the value of R1 as compared to the values of R2 and R8 when R2=R4 and R8=R9, with the gain inversely proportional to the value of R1, (similar to a non-inverting op amp with gain where R1 would go to ground).
But I tend to avoid math, which I find tedious, so am not up to deriving the equation for that.