I was wondering if someone could help me learn the theory behind this as I'm pretty new to electronics and op-amps aren't my strength. I'm building a constant current discharge device and I am very curious why this works. The picture is from a video I was watching [ see bottom]
Why is I = Vin/R? I cant figure that out. If I attach a lipo battery (4.2V) to the load, shouldn't the current going down through the 1 ohm/5W resistor be I = 4.2/1ohm = 4.2A? Changing the trim pot changes the current, I don't fully understand that either. I've listened to the video over and over but it's not making any sense. Thank you in advance!
Why is I = Vin/R? I cant figure that out. If I attach a lipo battery (4.2V) to the load, shouldn't the current going down through the 1 ohm/5W resistor be I = 4.2/1ohm = 4.2A? Changing the trim pot changes the current, I don't fully understand that either. I've listened to the video over and over but it's not making any sense. Thank you in advance!
Attachments
-
238.4 KB Views: 17
-
238.4 KB Views: 94