I made a connector small board based on this document .In page no 21 you can see "4.5 Load Impedance variation".

You can see that (Figure 36) signal from Bode 100 channel 2 is coming to one end of the load board and the other end is connected to WPT coil.

My schematic is given below.




From Bode 100 signal is coming to BNC and I will select one load at time(either 1R,10R ,22R etc). and the Output of J1 is coming to WPT coil.

I made a mistake in the schematic,the J1's 1st PIN is ground and 2nd PIN is signal.But I connected 1st pin to Signal and 2nd PIN is ground.

The signal coming from Bode100 is an AC signal.My question is will this connection error has any impact or not.

 

Coax is used to shield the RF signal by grounding the outer shield layer of the coax. If RF signal shielding is not needed, neither is coax.

 

The BNC connector on the left of your diagram is coming from the wireless power receiver coil, right? If that is the case, it does not matter which output you connect to ground of the analyzer since the entire circuit is floating.

For clarity, just move the ground symbol in your schematic.

 

No BNC connector on the left is connected to Bode-100.

 

Then the one on the right is the receiver coil?

It certainly does not matter which wire of the coil is connected to ground.

When drawing circuits, the convention is that signals flow from left to right. That is why assumed the one on the left was the receiver coil.