Hi everyone,
So, as I am reading this part of amazing book, the Celsius zero shift for two terminal temperature sensor circuit of Fig 21.19 is not fully understood by me.
what I understood:
The \[ V_{\text{Temp}} \] at the two terminal of the Zenner diode is directly coming from the circuit Fig.21.18 which is the output is of value (10mV/K)*T
the current frlowing through the V(not in) is the sum of Vo/10Kohm+Vref/9.16Kohm.
the only time I get the Vo=2.73V is when the \[ V_{\text{Temp}}=0 \] and a that value the current flowing through the V(not in) is negligible.
What I did not understand:
1where did the formula come from, it is like converting Kelvin to Celsius? \[ V_{\text{o}}=\left(\frac{10\text{mV}}{\text{Celsius}}\right) v\]
2what does the \[ v\] stand for?
3at C=0, it means Tk=273Kelvin and then V_temp=10*273=2.73V which bring the Vo~=0V?
here , is the page of the book and falstad simulator:
So, as I am reading this part of amazing book, the Celsius zero shift for two terminal temperature sensor circuit of Fig 21.19 is not fully understood by me.
what I understood:
The \[ V_{\text{Temp}} \] at the two terminal of the Zenner diode is directly coming from the circuit Fig.21.18 which is the output is of value (10mV/K)*T
the current frlowing through the V(not in) is the sum of Vo/10Kohm+Vref/9.16Kohm.
the only time I get the Vo=2.73V is when the \[ V_{\text{Temp}}=0 \] and a that value the current flowing through the V(not in) is negligible.
What I did not understand:
1where did the formula come from, it is like converting Kelvin to Celsius? \[ V_{\text{o}}=\left(\frac{10\text{mV}}{\text{Celsius}}\right) v\]
2what does the \[ v\] stand for?
3at C=0, it means Tk=273Kelvin and then V_temp=10*273=2.73V which bring the Vo~=0V?
here , is the page of the book and falstad simulator:
Attachments

1 KB Views: 5