Generally, which type of switching regulator has more losses, lower efficiency: CC or CV?
For comparison, assume same power watts.
For comparison, assume same power watts.
All else being equal, they're pretty much the same, efficiency-wise, except of the extra power dissipated by the current-sense resistor in a CC regulator.Generally, which type of switching regulator has more losses, lower efficiency: CC or CV?
For comparison, assume same power watts.
Even during transients?All else being equal, they're pretty much the same, efficiency-wise, except of the extra power dissipated by the current-sense resistor in a CC regulator.
I don't know what you mean. Provide an actual use case, maybe show some schematics. Identify the source and magnitude of such transients. What is your end goal here?Even during transients?
The power parts for both regulators are the same. The only difference is how the error amplifier works.which type of switching regulator has more losses, lower efficiency: CC or CV?
Why do you think transients would significantly affect efficiency, since they are, by definition, short?Even during transients?
I asked because my understanding is that the larger the difference between Vin and Vout, the harder the converter has to work. True?All else being equal, they're pretty much the same, efficiency-wise
Normally, that would be rather small compared to the power-path, correct?except of the extra power dissipated by the current-sense resistor in a CC regulator.
To:All else being equal...
With the conclusion that:Converter:
- CV: Output 100V, load is drawing 0.5A (0.5A reserve)
vs
- CC: Output 2V, load is drawing 25A (50A reserve)
?You'd expect similar efficiency?
The current sense resistor is in the power path, and dissipates I²R.Normally, that would be rather small compared to the power-path, correct?
For a linear regulator the heat loss is larger with increased Vin-Vout.the larger the difference between Vin and Vout, the harder the converter has to work. True?
I don' t understand. I will assume " Vin = 1V @ 100A available = 100W available" is how the current is measured. No one in their right mind will make a current measuring circuit that eats up 100 W. I have made many LED CC power supplies, and we often used 0.1V for feedback for at 1A load. At 100A I would use a Hall sensor that has about zero voltage drop. There are other ways of measuring current. One is to look across the resistive part of an inductor which is in the switcher. This way adds no heat loss. Another method I use is to watch the voltage drop across the power MOSFET in the switcher. While there are some errors in the measurement it also does not add power loss.My example might be incorrect:
Assume Vin = 1V @ 100A available = 100W available.
Converter:
- CV: Output 100V, load is drawing 0.5A (0.5A reserve)
vs
- CC: Output 2V, load is drawing 25A (50A reserve)
Hi,Generally, which type of switching regulator has more losses, lower efficiency: CC or CV?
For comparison, assume same power watts.
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