Hi, am trying to calculate capacitor value for full wave bridge rectifier with reference to below formula
C = Laod Current × Capacitor discharge time ÷ acceptable ripple amplitude
I.e.
C = (I × T÷2) ÷ (ΔV)
Capacitor discharge time is approximated to T/2 for full wave bridge rectifier.
For, I = 2.2 A, ΔV = 2V and,
(T÷2) = 1 ÷ (2 × F) =1 ÷ (2 × 50Hz) = 10ms
Thus substituting these values in above equation, i get,
C= 2.2A × 10ms ÷ 2V = 11000 μF
Do I need such a big Capacitor??
Am i going wrong anywhere..?
C = Laod Current × Capacitor discharge time ÷ acceptable ripple amplitude
I.e.
C = (I × T÷2) ÷ (ΔV)
Capacitor discharge time is approximated to T/2 for full wave bridge rectifier.
For, I = 2.2 A, ΔV = 2V and,
(T÷2) = 1 ÷ (2 × F) =1 ÷ (2 × 50Hz) = 10ms
Thus substituting these values in above equation, i get,
C= 2.2A × 10ms ÷ 2V = 11000 μF
Do I need such a big Capacitor??
Am i going wrong anywhere..?