Cannot Run A Transient Analysis On This Two-Stage Amplifier

Thread Starter

newbie2019

Joined Apr 5, 2019
95
Here's the circuit from post #14 with some local emitter negative feedback in the last stage, which significantly reduces the distortion.
To view the harmonic distortion percentage, use the .four command as shown, and look in the View/Spice error log after doing the simulation.
Such feedback in the first stage should give a further reduction in distortion (with a reduction in gain that negative feedback always gives, of course).

View attachment 177613
Thanks crutschow this is very helpful. With this circuit the THD is 1.67%, is that a lot of distortion?

I then modified the circuit by adding some negative emitter feedback to stage 1. The THD dropped to 0.61%.

Finally, I added two-stage feedback and that reduced the THD to 0.16%.

2019
 

Audioguru

Joined Dec 20, 2007
11,248
Many people can hear 0.1% distortion. People who are tone deaf and do not like music cannot hear 50% distortion.
In your circuit the amount of distortion increases a lot if the input level increases so all the peak levels of music and speech from your amplifier will be terribly distorted.

You never answered what is your tiny input signal and why is its level so low. A microphone level is at least 20 times higher.
You also never answered why are all the resistors values so low and the capacitor values so high.

Your circuit came from a book. Many (all?) books, professors and teachers make mistakes you know.






many books
 

Thread Starter

newbie2019

Joined Apr 5, 2019
95
That's only true if the amp open-loop gain is infinite (or very high).
That's not true in this case, so you have to include the finite open-loop gain in your closed-loop gain calculation.
Thanks. I will do some research regarding open-loop gain and closed-loop gain.
 
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Thread Starter

newbie2019

Joined Apr 5, 2019
95
Thanks. I will do some research regarding open-loop gain.
Here is my calculation.

Av(no feedback) = 556

β = RE1 / RE1 + RF = 50Ω / 50Ω + 18KΩ = 0.00277

Av(with feedback) = A(no feedback) / 1 + [A(no feedback) * β] = 556 / 1 + [556 * 0.00277] = 219

The gain per the sim is 207. Have I done the calculation correctly?
 
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Audioguru

Joined Dec 20, 2007
11,248
My simulation shows that with an input of 0.5mV peak then its output is a little higher than 100mV peak so it gain is a little more than 200.
 
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