Using a design for a DC-AC HV Inverter, previously developed with the help of this forum, I aim to produce an output of 1kV to 10kV when this is used with a flyback transformer, shown in the other image. However, I'm unsure how to derive the number of turns in each half of the primary with its wind yourself coil.


I understand that in this setup, the output voltage will be a function of the frequency (via the change in coil reactance) and the output current a function of the duty cycle. I'm aiming for the 10kV output to occur at around 30-35kHz. I believe the following parameters are relevant to the calculation of the number of primary turns:
MOSFET supply: 12.0 - 12.5V
Frequency range: 10kHz - 50kHz
Duty cycle: 10-90%
Idle current: 50-100mA (a guesstimate)
Desired output voltage: 1kV - 10kV
Flyback secondary turns: 2400
Proposed primary coil wire: AWG 16 (1.3mm dia)
Primary former CSA: 2.75cm^2
Any help would be appreciated.


I understand that in this setup, the output voltage will be a function of the frequency (via the change in coil reactance) and the output current a function of the duty cycle. I'm aiming for the 10kV output to occur at around 30-35kHz. I believe the following parameters are relevant to the calculation of the number of primary turns:
MOSFET supply: 12.0 - 12.5V
Frequency range: 10kHz - 50kHz
Duty cycle: 10-90%
Idle current: 50-100mA (a guesstimate)
Desired output voltage: 1kV - 10kV
Flyback secondary turns: 2400
Proposed primary coil wire: AWG 16 (1.3mm dia)
Primary former CSA: 2.75cm^2
Any help would be appreciated.