Uh... no.
hey there, thank you for replying. While this may seem like a homework it unfortunately isnt since it contributes to my module percentage by 40%,so essentially its a coursework. I havent had time to learn C due to other modules taking up my time, but after watching BroCodes 6 hour video on C, i developed a rough understanding. Using your idea I have written a code but im not sure if its working as intended because my output will not print the print statement. I appreciate your guidance. leap years are not considered for this code
Hey there, thank you for your response. Yes I completely agree with your idea about solving a problem is to struggle with them, which is something I usually do when given time. However, in my case I cannot do that due to time constraints, But ive gained a decent amount of basic understanding for C within the past 2 days. Ive broken down my code into parts so i can get each one of them working then connect it together, but it seems like the code ive written so far is not working. I have taken a simliar approach to your three bullet points.
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#include <stdio.h>
// Function to check if a year is a leap year
int isLeap(int year) {
// Leap year occurs on every year that is exactly divisible by 4,
// except for years that are exactly divisible by 100,
// but these centurial years are leap years if they are exactly divisible by 400.
if (year % 400 == 0) {
return 1;
} else if (year % 100 == 0) {
return 0;
} else if (year % 4 == 0) {
return 1;
} else {
return 0;
}
}
// Function to calculate the number of days since the beginning of the year
int days_since_beginning_of_year(int day, int month, int year) {
// Array of cumulative days before each month in a non-leap year (0-indexed for Jan-Dec)
int days_before_month[] = {0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334};
int day_of_year = days_before_month[month - 1] + (day - 1);
// If the date is after February and it is a leap year, add an extra day
if (month > 2 && isLeap(year)) {
day_of_year += 1;
}
return day_of_year + 1; // Add 1 because Jan 1st is day 1, not day 0
}
int main() {
int day, month, year, days_elapsed;
// Example 1: Non-leap year
day = 15;
month = 3; // March
year = 2023;
days_elapsed = days_since_beginning_of_year(day, month, year);
printf("Days since beginning of year %d/%d/%d: %d\n", month, day, year, days_elapsed);
// Example 2: Leap year (February 29th)
day = 29;
month = 2; // February
year = 2024;
days_elapsed = days_since_beginning_of_year(day, month, year);
printf("Days since beginning of year %d/%d/%d: %d\n", month, day, year, days_elapsed);
// Example 3: Leap year date after Feb
day = 1;
month = 3; // March
year = 2024;
days_elapsed = days_since_beginning_of_year(day, month, year);
printf("Days since beginning of year %d/%d/%d: %d\n", month, day, year, days_elapsed);
return 0;
}thank you for your reply. The code you sent doesnt work as intended and im not considering leap years for this code since its what ive been asked.
#include <stdio.h>
#include <math.h>
int main()
{
int noofdaysinmonth[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30 ,31}; /*this array handles the number of days in the month*/
int day1 = 0, month1 = 0, year1 = 0;
int day2 = 0, month2 = 0, year2 = 0;
int totaldays = 0;
int totaldays1 = 0;
int totaldays2 = 0;
totaldays1 = year1 * 365; /*calculates number of days in the year*/
printf("\nEnter first date: ");
scanf("%d/%d/%d", &day1, &month1, &year1);
printf("You entered: day1 = %d, month1 = %d, year1 = %d\n", day1, month1, year1);
if((year1 <= 0 || year1 > 9999) || (day1 > noofdaysinmonth[month1 - 1]|| day1 < 1) || (month1 < 1 || month1 > 12)){
fprintf(stderr, "INVALID DATE"); /*this if statement block checks if the entered date is in the specified range. If not, it prints error using stderr*/
}
else{
printf("first date is invalid");
}
totaldays2 = year2 * 365; /*calculates number of days in the year*/
printf("\nEnter second date: ");
scanf("%d %d %d", &day2, &month2, &year2);
printf("You entered: day2 = %d, month2 = %d, year2 = %d\n", day2, month2, year2);
if((year2 <= 0 || year2 > 9999) || (day2 > noofdaysinmonth[month2 - 1]|| day2 < 1) || (month2 < 1 || month2 > 12)){
fprintf(stderr, "INVALID DATE"); /*this if statement block checks if the entered date is in the specified range. If not, it prints error using stderr*/
}
else{
printf("second date is invalid");
}
totaldays = totaldays2 - totaldays1;
return 0;
}
thank you very much for your response. This code seems abit too advanced for me, sadly. Im also using VScode.
i really appreciate your help. I fixed my messy code and its just working similarly to this, and i also recalled the functions, but im not getting any days calculations. I havent made my code as clean as yours since my professor is not expecting that much from me, but still you made the code easier to read and thank you. Moreover, i need the functions because we have learnt that in our module.
yeah i forgot to make a print statement for that, its working now but the calculations are wrong, and the code doesnt print "invalid date" if the first date is invalid. It prints it after both dates are entered
#include <stdio.h>
#include <math.h>
int main()
{
int noofdaysinmonth[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30 ,31}; /*this array handles the number of days in the month*/
int day1 = 0, month1 = 0, year1 = 0;
int day2 = 0, month2 = 0, year2 = 0;
int totaldays = 0;
int totaldays1 = 0;
int totaldays2 = 0;
totaldays = totaldays2 - totaldays1;
printf("enter your first date: ");
scanf("%d/%d/%d", &day1, &month1, &year1);
printf("enter your second date: ");
scanf("%d/%d/%d", &day2, &month2, &year2);
int datecalculation1()/*this function checks if date is valid and calculates the number of days from entered year*/
{
if((year1 <= 0 || year1 > 9999) || (day1 > noofdaysinmonth[month1 - 1]|| day1 < 1) || (month1 < 1 || month1 > 12)) {
fprintf(stderr, "INVALID DATE"); /*this if statement block checks if the entered date is within the specified range. If not, it prints error using stderr*/
}
else{
totaldays1 = (year1 * 365); /*calculates number of days in the year*/
}
}
datecalculation1();
int datecalculation2()/*this function checks if date is valid and calculates the number of days from entered years*/
{
if((year2 <= 0 || year2 > 9999) || (day2 > noofdaysinmonth[month2 - 1]|| day2 < 1) || (month2 < 1 || month2 > 12)){
fprintf(stderr, "INVALID DATE"); /*this if statement block checks if the entered date is in the specified range. If not, it prints error using stderr*/
}
else{
totaldays2 = (year2 * 365); /*calculates number of days in the year*/
}
}
datecalculation2();
printf("%d", totaldays);
return 0;
}thank you. i tried fixing it, the code partially works. i also have no idea about what return 0 and 1 seem to do, but i added it and it solved one tiny problem i guess
#include <stdio.h>
#include <math.h>
int noofdaysinmonth[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30 ,31}; /*this array handles the number of days in the month*/
int day1 = 0, month1 = 0, year1 = 0;
int day2 = 0, month2 = 0, year2 = 0;
int totaldays1 = 0;
int totaldays2 = 0;
int datecalculation1()/*this function checks if date is valid and calculates the number of days from entered year*/
{
printf("enter your first date: ");
scanf("%d/%d/%d", &day1, &month1, &year1);
if((year1 <= 0 || year1 > 9999) || (month1 < 1 || month1 > 12) || (day1 > noofdaysinmonth[month1 - 1]|| day1 < 1)) {
fprintf(stderr, "INVALID DATE\n"); /*this if statement block checks if the entered date is within the specified range. If not, it prints error using stderr*/
return 0;
}
else{
totaldays1 = year1 * 365; /*calculates number of days in the year*/
return 1;
}
}
int datecalculation2()/*this function checks if date is valid and calculates the number of days from entered years*/
{
printf("enter your second date: ");
scanf("%d/%d/%d", &day2, &month2, &year2);
if((year2 <= 0 || year2 > 9999) || (month2 < 1 || month2 > 12) || (day2 > noofdaysinmonth[month2 - 1]|| day2 < 1)){
fprintf(stderr, "INVALID DATE\n"); /*this if statement block checks if the entered date is in the specified range. If not, it prints error using stderr*/
return 0;
}
else{
totaldays2 = year2* 365; /*calculates number of days in the year*/
return 1;
}
}
int main()
{
datecalculation1();
datecalculation2();
int totaldays = totaldays2 - totaldays1;
if(totaldays == 0){
return 0;
}
else{
printf("%d", totaldays);
}
return 0;
}Let's look at the initial code you provided and make sure that you understand what it is doing and why it is behaving the way it is:
#include <stdio.h>
#include <math.h>
int noofdaysinmonth[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30 ,31}; /*this array handles the number of days in the month*/
int day1 = 0, month1 = 0, year1 = 0;
int day2 = 0, month2 = 0, year2 = 0;
int main()
{
int datecalculation1()/*this function checks if date is valid and calculates the number of days from entered years*/
{
if((year1 <= 0 || year1 > 9999) || (day1 > noofdaysinmonth[month1 - 1]|| day1 < 1) || (month1 < 1 || month1 > 12))
{
fprintf(stderr, "INVALID DATE"); /*this if statement block checks if the entered date is in the specified range. If not, it prints error using stderr*/
return 0;
}
else
{
return 1;
int totaldays = 0;
totaldays = year1 * 365; /*calculates number of days in the year*/
printf("enter your first date: ");
scanf("%d/%d/%d", &day1, &month1, &year1);
}
}
return 0;
}int main()
{
// Define a function named datecalculation1()
return 0;
}
