Hello everybody, this is the first time I write on AAC's forum.
As the title says, i'm wondering how to estimate the dischaging time of a battery from , for example, 12V to 9.5V.
I'm projecting a Buck regulator for a guitar pedal board and I need 9V and, at least, 500mA output.
As source I thought for a 12V Li-Ion battery and, as a concequence of some preliminary steps, I obtained:
Duty=Vout/Vin=9/12=0.75
Iin=Iout*Duty=500*0.75=375 mA
If I think an average use of 4h (a very big gig
), I need a battery whose capacity is 375*4=1500 mAh
But here comes the problem:
the Vin mustn't fall below 9V (I have a buck regulator) and the 1500mAh are calculated in relation, IMHO, to a battery discharging from the rated voltage to the threshold voltage,which can be few volts.
How can I calcolate the minimum capacity of the battery that guarantees the operating condition of 500 mA*4 h knowing that I can't go below 9 V?
I'm sorry for the bad english, this isn't my mother tongue
As the title says, i'm wondering how to estimate the dischaging time of a battery from , for example, 12V to 9.5V.
I'm projecting a Buck regulator for a guitar pedal board and I need 9V and, at least, 500mA output.
As source I thought for a 12V Li-Ion battery and, as a concequence of some preliminary steps, I obtained:
Duty=Vout/Vin=9/12=0.75
Iin=Iout*Duty=500*0.75=375 mA
If I think an average use of 4h (a very big gig
But here comes the problem:
the Vin mustn't fall below 9V (I have a buck regulator) and the 1500mAh are calculated in relation, IMHO, to a battery discharging from the rated voltage to the threshold voltage,which can be few volts.
How can I calcolate the minimum capacity of the battery that guarantees the operating condition of 500 mA*4 h knowing that I can't go below 9 V?
I'm sorry for the bad english, this isn't my mother tongue